-6,-2,0,1,3/2 whats the sequence and what do I multiply by

A student spends 17/35 of his pocket money on transport and fruits. He spends 5/6 of the remainder on sweets. What fraction of h

Mashutka [201]

Answer: 3/7 is the pocket money he spends on sweets

Step-by-step explanation:

Let the amount student spends be x

He spends 17/35x on transport and fruits

He spends 5/6 (x - 17/35x) on sweets

5/6 * (x -17/35x)

5/6 * 18/35x

= 3/7x

6 0

2 years ago

Jeanne wants to start collecting coins and orders a coin collection starter kit. The kit comes with three coins chosen at random

lesya692 [45]

Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes $P_B(A)$ .

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
$P(A|B)= \frac{P(A \cap B)}{P(B)}$

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is $\frac{1}{3}$

Part A:
To find the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus $P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}$

P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

Thus $P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}$

Therefore, $P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}$

Part B:
To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.

$P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}$

 $P(D)= \frac{1}{3}$ 

Therefore, $P(C|D)=\left( \frac{ \frac{2}{9} }{ \frac{1}{3} } \right)= \frac{2}{3}$

3 0

2 years ago

The distance between Cincinnati, Ohio, and charlotte, North Carolina, is about 336 miles.The distance between Cincinnati and Chi

bija089 [108]

Cincinnati Ohio à Charlote North CA = a total of 336 miles
Cincinnati à Chicago Illinois = a total of 247 miles
Perry drove from Charlote to Chicago by passing Cincinati. Find the distance she drove.
=> Note that the distance from charlotte to Cincinnati is 365 then from Cincinnati to Chicago is 247
=> 336 miles + 247 Miles
=> 583 miles
Penny drove for a total of 583 miles from Charlotte to Cincinnati to Chicago.

8 0

2 years ago

If pentagon ABCDE is rotated 180 degrees around the origin to create pentagon A’B’C’D’E’, what is the ordered pair of point A’?

Semmy [17]

Answer:

(A)

Step-by-step explanation:

Point A is at (-2,4)

Rule of a 180° rotation about the origin: (x,y) --> (-x,-y)

Using the rule, (-2,4) will become (2,-4).

A' should be (2,-4) or Option A.

4 0

2 years ago

Find the coordinates of the midpoint of LB if L(8,5) and B(-6,2) 10 points!!!

KATRIN_1 [288]

Answer:

A, (1, 3+1/2)

Step-by-step explanation:

Midpoint formula for reference: m= {(x1 + x2)/2, (y1 + y2)/2}

Plugging in the points we get: m= {(8 - 6)/2, (5 + 2)/2}

Now we simplify using PEMDAS. First step is parentheses.

m= {2/2, 7/2}

Simplifying again (and making 7/2 a mixed number), it becomes

m= {1, 3+1/2}

Hope this helps!

3 0

1 year ago