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lyudmila [28]
2 years ago
12

-6,-2,0,1,3/2 whats the sequence and what do I multiply by

Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
5 0
Its not possible because if you try to multiply back and forth it wont work. 

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Forty-two percent of primary care doctors think their patients receive unnecessary medical care (reader's digest, december 2011/
igomit [66]

Answer:

The standard error is 0.02849

Step-by-step explanation:

<u>Explanation:</u>-

given data is 42% of primary case doctors think their patients receive un-necessary medical care.

That is The proportion 'p' = 42% = 0.42

Given sample size is n =300

The standard error of the sampling distribution of the sample proportion is

se (p) = \frac{\sqrt{p(1-p)} }{\sqrt{n} }

se (p) = \frac{\sqrt{0.42(1-0.42))} }{\sqrt{300} }

use calculator on simplification , we get

standard error = 0.02849

5 0
2 years ago
Nate is creating a PSA about building a "green” roof. Which source is most reliable for his research? a blog post written by a c
galina1969 [7]

Answer:

Nate wants to use a .org (or .gov) site about ecological roofs, a book featuring photos of different styles of room  because

1. It specifically talks about green roof's

2. Unlike the blog post, the .org/.gov is not attempting to sell a product that may change how the article is written.

7 0
2 years ago
You jog 6/23 miles around a track each day. If you jogged that distance 4 times last week, how many miles did you jog?
LenaWriter [7]
Well, since you jogged 6/23 mi. a day, for 4 days, it'll be (6/23)×4. This is 24/23 which is one mile and 1/24 of one.
6 0
2 years ago
Four students wrote sequences during math class. Andre mc011-1.jpg Brenda mc011-2.jpg Camille mc011-3.jpg Doug mc011-4.jpg Which
maks197457 [2]
<span>A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.

</span>The common ration is obtained by dividing the a term by the preceding term.

Given that f<span>our students wrote sequences during math class with
Andre writing -\frac{3}{4} ,\frac{3}{8} ,-\frac{3}{16} ,-\frac{3}{32} , . . .
Brenda writing </span>\frac{3}{4} ,-\frac{3}{8} ,\frac{3}{16} ,\frac{3}{32} , . . .
Camille writing \frac{3}{4} ,\frac{3}{8} ,-\frac{3}{16} ,-\frac{3}{32} , . . .
Doug writing \frac{3}{4} ,-\frac{3}{8} ,\frac{3}{16} ,-\frac{3}{32} , . . .

Notice that the common ratio for the four students is - \frac{1}{2}.

For Andre, the last term is wrong and hence his sequence is not a geometric sequence.
For Brenda, the last term is wrong and hence her sequence is not a geometric sequence.
For Camille, her sequence is not a geometric sequence.
For Doug, his sequence is a geometric sequence with a common ratio of - \frac{1}{2}.

Therefore, Doug wrote a geometric sequence.
8 0
2 years ago
Read 2 more answers
HELP ASAP In two or more complete sentences, Explain how you would find the equation of a parabola, given the coordinate of the
kvasek [131]
In the general case in Cartesian coordinates, you would use the definition of a parabola as the locus of points equidistant from the focus and directrix. The equation would equate the square of the distance from a general point (x, y) to the focus with the square of the distance from that point to the directrix line.

Suppose the focus is located at (h, k) and the equation of the directrix is ax+by+c=0. The expression for the square of the distance from (x, y) to the point (h, k) is ...
  (d₁)² = (x-h)²+(y-k)²
The expression for the square of the distance from (x, y) to the directrix line is
  (d₂)² = (ax+by+c)²/(a²+b²)

Equating these expressions gives the equation of the parabola.
  (x-h)²+(y-k)² = (ax+by+c)²/(a²+b²)

When the directrix is parallel with one of the axes, one of the coefficents "a" or "b" is zero and the equation becomes much simpler. Often, it would be easier to make use of the formula (for a directrix parallel to the x-axis):
  y = 1/(4p)*(x -h)² +k
where the (h, k) here is the vertex, the point halfway between the focus and directrix, and "p" is the (signed) distance from the focus to the vertex. (p is positive when the focus is above or to the right of the vertex.)
4 0
2 years ago
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