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kipiarov [429]
1 year ago
7

If →u and →v are the vectors below, find the vector →w whose tail is at the point halfway from the tip of →v to the tip of →v−→u

and whose head is at the point halfway from the tip of →u to the tip of →v. Assume all vectors are in standard position.
u: (-1,-1,-1) v:(2,3,-5)
Mathematics
1 answer:
S_A_V [24]1 year ago
5 0
Û = (-1, -1, -1)
^v = (2, 3, -5)
^v - û = (2 + 1, 3 + 1, -5 + 1) = (3, 4, -4)
Half way from ^v to ^(v - u) = ((3 - 2)/2, (4 - 3)/2, (-4 + 5)/2) = (1/2, 1/2, 1/2)
Halfway from û to ^v = ((2 + 1)/2, (3 + 1)/2, (-5 + 1)/2) = (3/2, 2, -2)

The required vector ^w = ((3/2 - 1/2), (2 - 1/2), (-2 - 1/2)) = (1, 1/2, -5/2)
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Particle travels along a circular path that has a radius of 3 feet. The angular velocity of the particle is 18 radians per minut
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6 0
1 year ago
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Ephemeral services corporation (esco) knows that nine other companies besides esco are bidding for a $900,000 government contrac
EastWind [94]

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c. $100,000

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E(X) = (1/9) × $900,000

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4 0
1 year ago
Given triangle GHJ, the measure of angle G equals 110°, the measure of angle J equals 40°, and the measure of angle H equals 30°
tester [92]

Answer:

Since angle G is  

✔ the largest

 angle, the opposite side, JH, is  

✔ the longest side

. The order of the side lengths from longest to shortest is  

✔ HJ, GH, and GJ

.

Step-by-step explanation:

5 0
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In △ABC, m∠ABC=40°,
Alchen [17]

Let m∠CLN = x. Then m∠ALM = 3x, and m∠A = 90°-x, m∠C = 90°-3x.

The sum of angles of ∆ABC is 180°, so we have

... 180° = 40° + m∠A + m∠C

Using the above expressions for m∠A and m∠C, we can write ...

... 180° = 40° + (90° -x) + (90° -3x)

... 4x = 40° . . . . . . . . . add 4x-180°

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The ratio of CN to CL is

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... CN/CL = 1/2

so ...

... CN = (1/2)CL

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