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kipiarov [429]
2 years ago
7

If →u and →v are the vectors below, find the vector →w whose tail is at the point halfway from the tip of →v to the tip of →v−→u

and whose head is at the point halfway from the tip of →u to the tip of →v. Assume all vectors are in standard position.
u: (-1,-1,-1) v:(2,3,-5)
Mathematics
1 answer:
S_A_V [24]2 years ago
5 0
Û = (-1, -1, -1)
^v = (2, 3, -5)
^v - û = (2 + 1, 3 + 1, -5 + 1) = (3, 4, -4)
Half way from ^v to ^(v - u) = ((3 - 2)/2, (4 - 3)/2, (-4 + 5)/2) = (1/2, 1/2, 1/2)
Halfway from û to ^v = ((2 + 1)/2, (3 + 1)/2, (-5 + 1)/2) = (3/2, 2, -2)

The required vector ^w = ((3/2 - 1/2), (2 - 1/2), (-2 - 1/2)) = (1, 1/2, -5/2)
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Make b the subject of this formula. a=9b
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Answer:

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A taxi cab charges $0.55 per mile in addition to a $1.75 flat rate fee. Susie has $10 to spend on a taxi cab ride. The taxi driv
Olenka [21]
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6 0
2 years ago
PLEASE HEP ASAP!!!!!!! 30 POINTS!!!!!
anzhelika [568]

Answer:

a) 42°F < x < 176°F

b) The inequality graph is attached.

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Step-by-step explanation:

According to the Question,

a) For the benzene to remain in liquid form, the temperature of benzene must be less than the boiling point and greater than the boiling point. Let x be the temperature of benzene, For benzene to remain as liquid, its temperature must be between:

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b) The inequality graph is attached. The graph shows that the temperature of benzene must be between 42°F and 176°F so that it would be a liquid. The Closed circles represent that it is greater than 2.

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2 years ago
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Vitek1552 [10]
<h2>Answer with explanation:</h2>

To write an inequality and show on a number line all numbers: greater than (−3) but less than or equal to 3

Let n be the number, then -3 < n ≤3 .

On number line we mark open circle at -3 (since it has a strictly less than sign) and a closed circle at 3  (since it has a less than and equal to sign) .

To the required inequality that shows all the numbers greater than (−3) but less than or equal to 3 : -3 < n ≤3 and the number line is represented below.

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