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iragen [17]
2 years ago
9

Elise has budgeted $800 in her checking account to spend during the summer for entertainment. She would like to have at least $2

00 available at the end of summer. If elise withdraws $50 per week, which inequality could she use to determine the greatest number of weekly withdrawals (w) she can make without exceeding her budget?
Mathematics
2 answers:
ankoles [38]2 years ago
7 0

To represent the inequality, let us define some variables first:

lets say 'w' represents the greatest number of weekly withdrawals:

Elise has budget of $800 in her checking account:

If she withdraws $50 each week then in 'w' number of weeks she has withdrawn 50 \times x dollars.

The amount left in her checking account is given by:

800-50\times x

Now, she needs to have at least $200 available at the end of summer.

Which means:

800-50\times x\geq 200

The inequality 800-50x\geq 200 can be used to determine the greatest number of weekly withdrawals.

kogti [31]2 years ago
3 0

Answer:

800-50w≥200 have a great day

Step-by-step explanation:

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Answer:

Step-by-step explanation:

66 mile per hour .

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2 years ago
The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of
slavikrds [6]

Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

X = 30000

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 29858}{5600}

Z = 0.02

Z = 0.02 has a pvalue of 0.5080.

X = 20000

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.5080 - 0.0392 = 0.4688

c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

This is the value of X when Z has a pvalue of 0.95. So this is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

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2 years ago
Transversal CD←→ cuts parallel lines PQ←→ and RS←→ at points X and Y as shown in the diagram. If m∠CXP = 106.02°, what is m∠SYD?
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<span>m∠SYD = </span>106.02°
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8 0
1 year ago
Read 2 more answers
Data sets A and B are dependent. Find sd.Assume that the paired data came from a population that is normally distributed.A. 1.73
marusya05 [52]

Complete question :

A : 2.7, 3.7, 5.6, 2.6, 2.7

B : 5.1, 4.0, 3.9, 3.8, 5.2

Data sets A and B are dependent. Find sd.Assume that the paired data came from a population that is normally distributed.A. 1.73B. 1.21C. 1.32D. 1.89

Answer: A.1.73

Step-by-step explanation:

Given the data:

A : 2.7, 3.7, 5.6, 2.6, 2.7

B : 5.1, 4.0, 3.9, 3.8, 5.2

Difference betweenA and B (A - B) :

Xd = (A - B) = - 2.4, -0.3, 1.7, - 1.2, - 2.5

Sum of (A - B) = Σ Xd = (-2.4 + (-0.3) + 1.7 + (-1.2) + (-2.5) = - 4. 7

Md = ΣXd / n = - 4.7 / 5 = - 0.94

Xd - Md = (-2.4 + 0.94), (-0.3 + 0.94), (1.7 + 0.94), (-1.2 + 0.94), (-2.5 + 0.94)

(Xd - Md) = - 1.46, 0.64, 2.64, - 0.26, - 1.56

(Xd - Md)^2 = (-1.46)^2 + 0.64^2 + 2.64^2 + (-0.26)^2 + (-1.56)^2

Σ(Xd - Md)^2 = (2.1316 + 0.4096 + 6.9696 + 0.0676 + 2.4336) = 12.012

Standard deviation = √[Σ(Xd - Md)^2 / (n-1)]

Standard deviation= √12.012 / 4

Standard deviation = 1.7329

Standard deviation= 1.73

3 0
2 years ago
The value of a car is 18,500. It loses 10.3% of its value every year. Find the approximate monthly decrease in value. Round your
valentina_108 [34]

Answer:

$158.8

Step-by-step explanation:

There are 12 months in 1 year.

If in 1 year, it looses value of 10.3%, so in a month it will loose value of:

10.3%/12 = 0.8583% per month

So, to find the decreased value (in dollars) per month, we got to find 0.8583% of 18,500 dollars.

First, we need to convert percentage to decimal by dividing by 100. Then we multiply that to 18,500 to get our answer. So:

0.8583% = 0.8583/100 = 0.008583

Now,

0.008583 * $18,500 = $158.7855

Rounded to nearest tenth (1 decimal pae) = $158.8

6 0
2 years ago
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