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Svetllana [295]

1 year ago

10

At a track meet, the longest shot put throw by a boy is 25 feet and 8 inches. The longest shot put throw by a girl is 19 feet an

d 3 inches. How many times greater is the longest shot put throw by a boy than by a girl?
Please explain

2 answers:

MAVERICK [17]1 year ago

4 0

Its 6 feet and 5 inches

Hunter-Best [27]1 year ago

3 0

Answer:

difference = 6 feet 5 inches

Step-by-step explanation:

The longest shot put throw by a boy is given as 25 feet 8 inches . The longest shot put throw by a girl is given as 19 feet and 3 inches. The number of times the longest shot put throw by a boy is greater than by a girl can be computed as follow.

The question asked us to find the difference between the throw. The difference between the throw is the boy throw minus the girls throw. Mathematically,

The longest boys throw = 25 feet 8 inches

The longest girls throw = 19 feet 3 inches

difference = The longest boy throw - The longest girl throw

difference = 25 feet 8 inches - 19 feet 3 inches

difference = 6 feet 5 inches

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Answer:

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Step-by-step explanation:

Let's begin with the mass definition in terms of density.

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$\bar{y}=\frac{1}{M}\int\int y*\rho dydx$

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$\bar{y}=\frac{85}{28}$

Therefore the center of mass is:

$(\bar{x},\bar{y})=(5,\frac{85}{28})$

I hope it helps you!

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