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son4ous [18]
1 year ago
14

Ashley is making $500 a week at her job. She receives a 20% pay raise. A year later she gets a 5% pay cut. How much does she mak

e per week now?
Mathematics
1 answer:
notsponge [240]1 year ago
8 0

Answer:

Assuming Ashley didn't​ take any week off. Ashley earning in the first year:

500*52=$26000

She earns the second year:

26000 * 1.2 = $31200

She spent 5%

31200 * 0.05 = $1560

The remaining yearly earning:

31200 - 1560 = $29640

Weekly earning:

29640 ÷ 52 = $570


Read more on Brainly.com - brainly.com/question/3450376#readmore



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A referendum failed by a vote of 36 No's and 24 Yes's. To make a pie chart of this result, what is the lesser measure in degrees
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From the given number of people who voted Yes and No to the referendum, there are 60 people all in all. The fewer of which is 24 which voted as Yes. If we are to construct a pie chart and calculate the measure of the smaller angle, we take the ratio of 24 and 60 and multiply it to 360. 
      
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2 years ago
In the diagram of circle A, what is the measure of ∠XYZ?<br><br> 35°<br> 70°<br> 75°<br> 140°
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Answer:   First Option is correct.

Step-by-step explanation:

Since we have given that

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Measure of ∠XAZ = 105°

We need to find the measure of ∠XYZ.

As we know the angle subtended at the center is the average of the measure of arc intercepted by it angle and its vertical angles.

\frac{175^\circ+\angle XYZ}{2}=105^\circ\\\\175^\circ+\angle XYZ=210^\circ\\\\\angle XYZ=210^\circ-175^\circ\\\\\angle XYZ=35^\circ

Hence, the value of  ∠XYZ is 35°.

Hence, First Option is correct.

3 0
2 years ago
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Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4
vekshin1

<u>Given:</u>

The given equation is \log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)

We need to determine the extraneous solution of the equation.

<u>Solving the equation:</u>

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule \log _{c}(a)+\log _{c}(b)=\log _{c}(a b), we get;

\log _{4}(x(x-3))=\log _{4}(-7 x+21)

Again applying the log rule, if \log _{b}(f(x))=\log _{b}(g(x)) then f(x)=g(x)

Thus, we have;

x(x-3)=-7 x+21

Simplifying the equation, we get;

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x^2+4x-21=0

Factoring the equation, we get;

(x-3)(x+7)=0

Thus, the solutions are x=3, x=-7

<u>Extraneous solutions:</u>

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)

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Since, we know that \log _{a}(0) is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

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Simplifying, we get;

Undefined = \log _{4}(70)

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Thus, the solution x = -7 does not work in the original solution.

Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

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The right answer is:

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