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laiz [17]
2 years ago
12

If figure 1 is 3 then what is figure 100th

Mathematics
1 answer:
Alexxx [7]2 years ago
8 0
A) 3x100= 300 since figure 1 is 3 then figure 100 is 3x100
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Isoke is solving the quadratic equation by completing the square.10x2 + 40x – 13 = 0 10x2 + 40x = 13 A(x2 + 4x) = 13What is the
Elina [12.6K]

we have

10x^{2} + 40x - 13 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

10x^{2} + 40x =13

Factor the leading coefficient

10(x^{2} + 4x) =13 ----------> the value of A is 10

Complete the square. Remember to balance the equation by adding the same constants to each side

10(x^{2} + 4x+4) =13+40

10(x^{2} + 4x+4) =53

Rewrite as perfect squares

10(x+2)^{2} =53

10(x+2)^{2} =53  \\ (x+2)^{2} =\frac{53}{10} \\ \\ x+2=(+/-)\sqrt{\frac{53}{10}}  \\ \\ x1=-2+\sqrt{\frac{53}{10}}\\ \\ x2=-2-\sqrt{\frac{53}{10}}

therefore

the answer is

the value of A is 10

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2 years ago
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A student solved the problem below by first dividing 20 by 10. What mistake did the student make? A baseball team has won 20 gam
andreev551 [17]

Answer:


Step-by-step explanation: The student divided the number of wins by the number of losses.

The student should have divided the number of wins by the total number of games.

The student should have first added 20 and 10 to find that there were a total of 30 games.



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Lines m and p are perpendicular if the slope of line is 1, 25th what is the slope of line p
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-1 is the opposite reciprical (perpendicular)
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Emily wants to earn $100. She picks blueberries and is paid d dollars per bucket. She averages 4 buckets per day, and she has al
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Step-by-step explanation:

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2 years ago
se the function to show that fx(0, 0) and fy(0, 0) both exist, but that f is not differentiable at (0, 0). f(x, y) = 9x2y x4 + y
alexandr1967 [171]

Answer:

It is proved that f_x, f_y exixts at (0,0) but not differentiable there.

Step-by-step explanation:

Given function is,

f(x,y)=\frac{9x^2y}{x^4+y^2}; (x,y)\neq (0,0)

  • To show exixtance of f_x(0,0), f_y(0,0) we take,

f_x(0,0)=\lim_{h\to 0}\frac{f(h+0,k+0)-f(0,0)}{h}=\lim_{h\to 0}\frac{\frac{9h^2k}{h^4+k^2}-0}{h}\\\therefore f_x(0,0)=\lim_{h\to 0}\frac{9hk}{h^4+k^2}=\lim_{h\to 0}\frac{9k}{h^3+\frac{k^2}{h}}=0    exists.

And,

f_y(0,0)=\lim_{k\to 0}\frac{f(h,k)-f(0,0)}{k}=\lim_{k\to 0}\frac{9h^2k}{k(h^4+k^2)}=\lim_{k\to 0}\frac{9h^2}{h^4+k^2}=\frac{9}{h^2}   exists.

  • To show f(x,y) is not differentiable at the origin cheaking continuity at origin be such that,

\lim_{(x,y)\to (0,0)}\frac{9x^2y}{x^4+y^2}=\lim_{x\to 0\\ y=mx^2}\frac{9x^2y}{x^4+y^2}=\frac{9x^2\times m x^2}{x^4+m^2x^4}=\frac{9m}{1+m^2}  where m is a variable.

which depends on various values of m, therefore limit does not exists. So f(x,y) is not continuous at (0,0). Hence it is not differentiable at (0,0).

4 0
2 years ago
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