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laiz [17]
2 years ago
12

If figure 1 is 3 then what is figure 100th

Mathematics
1 answer:
Alexxx [7]2 years ago
8 0
A) 3x100= 300 since figure 1 is 3 then figure 100 is 3x100
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Jennifer has a bag of chips that contains 2 red chips and 1 black chips. If she also has a fair die, what is the probability tha
borishaifa [10]
Find each probability separately and then multiply the two together


Probability for even number is 3/6 or 1/2 because their are 3 even numbers out of 6 numbers

Probability to get a black chip is 1 black chip out of 3 totals so 1/3

Multiply 1/3 by 1/2

Answer 1/6
5 0
2 years ago
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I rent a gym for $150.00 for 30 students. Another time I rent the gym for $270.00 for 70 students. I need to find a fixed rate.
masha68 [24]

Answer: y = 3x + 60

<u>Step-by-step explanation:</u>

Set up two equations and solve the system:

 270 = 70x + b

- <u>(150 = 30x + b)</u>

  120 = 40x

    3   =  x

Input "x" into one of the equations and solve for "b":

150 = 30x + b

150 = 30(3) + b

150 = 90 + b

60 = b


Equation: y = 3x + 60

This means that there is a flat fee of $60 plus a rate of $3 per student


5 0
2 years ago
Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m
Dovator [93]

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.

8 0
2 years ago
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icang [17]

Answer:

A. $2.84

Step-by-step explanation:

8 0
2 years ago
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Compute E(X) for the following random variable X : X=Number of tosses until all 10 numbers are seen (including the last toss) by
julsineya [31]

Answer:

For 10 tosses we have that E(X)=10

Therefore E(i)= 1/10 +2/10 +3/10....10/10

This implies that 40/10=E(i)

Therefore E(10) =40/10

= 4.

8 0
1 year ago
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