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Eva8 [605]
2 years ago
11

At a fabric store, fabrics are sold by the yard. A dressmaker spent $36.35 on 4.25 yards of

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
8 0

Answer:

Silk = x = 1.5 yards

Cotton = y = 2.75 yards

Step-by-step explanation:

x + y = 4.25

16.90x + 4y = 36.35

1. The solution to the equation represent number of yards of silk and number of yards of cotton bought.

2.

x + y = 4.25 (1)

16.90x + 4y = 36.35 (2)

Multiply (1) by 4

4x + 4y = 17 (3)

16.90x + 4y = 36.35 (2)

Subtract (3) from (2)

16.90x - 4x = 36.35 - 17

12.90x = 19.35

Divide both sides by 12.90

x = 19.35 / 12.90

= 1.5

x = 1.5 yards

Substitute x = 1.5 yards into (1)

x + y = 4.25

1.5 + y = 4.25

y = 4.25 - 1.5

= 2.75

y = 2.75 yards

Silk = x = 1.5 yards

Cotton = y = 2.75 yards

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4 cups in a quart so you would have 72 cups divided by 4 and get 18
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2 years ago
In a statistics class, 10 scores were randomly selected with the following results: 74, 73, 77, 77, 71, 68, 65, 77, 67, 66. What
julia-pushkina [17]

Answer:

The 65th percentile is between 73 and 74

Step-by-step explanation:

Rearrange the ungrouped data in ascending order: 65,66,67,68,71,73,74,77,77,77

The 65th percentile is 65/100 of N ( N = 10) = 65/100 × 10 = 6.5

The 65th percentile is the 6.5th term. The 6th term is 73 and the 7th term is 74, the 6.5th term is between the 6th and 7th term

The 65th percentile is between 73 and 74

4 0
2 years ago
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Veronica put a $400 necklace on layaway by making a 10% down payment
JulsSmile [24]

7 weeks APEX LEARNING

7 0
2 years ago
The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of
slavikrds [6]

Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

X = 30000

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 29858}{5600}

Z = 0.02

Z = 0.02 has a pvalue of 0.5080.

X = 20000

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.5080 - 0.0392 = 0.4688

c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

This is the value of X when Z has a pvalue of 0.95. So this is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

5 0
2 years ago
A map shows the town where Niko lives. The actual distance from Niko's house to his school is 3 miles, and measures one-half inc
katrin2010 [14]

Answer:

<u>The distance of the library in the map is 0.67 inches (Rounding to two decimal places)</u>

Step-by-step explanation:

1. Let's review all the information given for solving this question:

Scale factor for the map of the town = 0.5 inches: 3 miles

Distance from Niko's house to his school = 3 miles

Distance from Niko's school to the library = 4 miles

2. Let's find the distance of the library in the map

Distance of the library in the map = Distance of the library * Scale factor

Distance of the library in the map = 4 miles * 0.5 inches:3 miles

Distance of the library in the map = (2 miles * inches)/3 miles

Distance of the library in the map = 2 inches/3 (Miles are cancelled in the numerator and in the denominator)

<u>Distance of the library in the map = 0.67 inches (Rounding to two decimal places)</u>

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2 years ago
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