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Montano1993 [528]

2 years ago

14

Which shows the four-term polynomial and factored form of x2 + 6x-27?

2 answers:

blsea [12.9K]2 years ago

7 0

Answer:

0x2+9x-3x-27 6x-27

Step-by-step explanation:

Crank2 years ago

3 0

Answer:

C

Step-by-step explanation:

You might be interested in

Half angle tan 5pi/8

Bond [772]

The half-angle formula for tangent is:

tan(a/2) = (sin a / (1 + cos a)) = ((1 - cos a) / sin a)

Now we can plug in values:

tan(5π/8) = (sin(5π/4) / (1 + cos(5π/4)) = ((1 - cos(5π/4)) / sin(5π/4)

tan(5π/8) = (-√2/2) / (1 + (-√2/2)) = (1 - (-√2/2)) / (-√2/2)

tan(5π/8) = ((-√2/2)) / ((2 - √2)/2) = ((2 + √2)/2) / (-√2/2)

Now we can solve the first half:

(-√2/2)(2 / (2 - √2))
(-√2/2)((4 + 2√2) / 2)
(-√2/2)(2 + √2)
(-2√2 - 2)/2
-√2 - 1

tan(5pi/8) = -√2 - 1

4 0

2 years ago

Traffic speed: The mean speed for a sample of cars at a certain intersection was kilometers per hour with a standard deviation o

aliina [53]

Answer:

Step-by-step explanation:

Hello!

X₁: speed of a motorcycle at a certain intersection.

n₁= 135

X[bar]₁= 33.99 km/h

S₁= 4.02 km/h

X₂: speed of a car at a certain intersection.

n₂= 42 cars

X[bar]₂= 26.56 km/h

S₂= 2.45 km/h

Assuming

X₁~N(μ₁; σ₁²)

X₂~N(μ₂; σ₂²)

and σ₁² = σ₂²

<em>A 90% confidence interval for the difference between the mean speeds, in kilometers per hour, of motorcycles and cars at this intersection is ________.</em>

The parameter of interest is μ₁-μ₂

(X[bar]₁-X[bar]₂)± $t_{n_1+n_2-2}$ * $Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$

$t_{n_1+n_2-2;1-\alpha /2}= t_{175; 0.95}= 1.654$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{134*16.1604+41*6.0025}{135+42-2} } = 3.71$

[(33.99-26.56) ± 1.654 *( $3.71*\sqrt{\frac{1}{135} +\frac{1}{42} }$ )]

[6.345; 8.514]= [6.35; 8.51]km/h

<em>Construct the 98% confidence interval for the difference μ₁-μ₂ when X[bar]₁= 475.12, S₁= 43.48, X[bar]₂= 321.34, S₂= 21.60, n₁= 12, n₂= 15</em>

$t_{n_1+n_2-2;1-\alpha /2}= t_{25; 0.99}= 2.485$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{11*(43.48)^2+14*(21.60)^2}{12+15-2} } = 33.06$

[(475.12-321.34) ± 2.485 *( $33.06*\sqrt{\frac{1}{12} +\frac{1}{15} }$ )]

[121.96; 185.60]

I hope this helps!

3 0

2 years ago

Solve the equation or inequality 3/2t-16=4/3t-6

Tamiku [17]

Answer:

<em>t=60</em>

Step-by-step explanation:

3/2t-16=4/3t-6

(subtract 4/3t from both sides)

3/2t-16-4/3t=-6

(add 16 to both sides)

3/2t-4/3t=-6+16

(simplify)

1/6t=10

(divide by 1/6 (or multiply by 6 on both sides)

t=60

7 0

2 years ago

Jose asks his friends to guess the higher of two grades he received on his math tests. He gives them two hints. The difference o

AlekseyPX

Answer : 96

x – y = 16 --------> equation 1

$\frac{1}{8} x +\frac{1}{2} y = 52$

x is the higher grade and y is the lower grade

We solve the first equation for y

x - y = 16

-y = 16 -x ( divide each term by -1)

y = -16 + x

Now substitute y in second equation

$\frac{1}{8} x +\frac{1}{2} ( -16 + x ) = 52$

$\frac{1}{8} x - 8 + \frac{1}{2} x = 52$

$\frac{1}{8} x + \frac{1}{2} x - 8 = 52$

Take common denominator to combine fractions

$\frac{1}{8} x + \frac{4}{8} x -8 = 52$

$\frac{5}{8} x - 8 = 52$

Add 8 on both sides

$\frac{5}{8} x = 60$

Multiply both sides by $\frac{8}{5}$

x = 96

We know x is the higher grade

96 is the higher grade of Jose’s two tests.

6 0

2 years ago

Read 2 more answers

Alexis has a rectangular piece of red paper that is 4 cm wide its length is twice its width she Glooze a rectangular r Alexis ha

UNO [17]

Are you looking for the area or the perimeter?

Perimeter: 24

Area: 32

Hope this helped!

-TTL

5 0

2 years ago

Read 2 more answers