Answer:
Remember that:
Speed = distance/time.
Then we can calculate the average speed in any segment,
Let's make a model where the average speed at t = t0 can be calculated as:
AS(t0) = (y(b) - y(a))/(b - a)
Where b is the next value of t0, and a is the previous value of t0. This is because t0 is the middle point in this segment.
Then:
if t0 = 100s
AS(100s) = (400ft - 0ft)/(200s - 0s) = 2ft/s
if t0 = 200s
AS(200s) = (1360ft - 50ft)/(300s - 100s) = 6.55 ft/s
if t0 = 300s
AS(300s) = (3200ft - 400ft)/(400s - 200s) = 14ft/s
if t0 = 400s
AS(400s) = (6250s - 1360s)/(500s - 300s) = 24.45 ft/s
So for the given options, t = 400s is the one where the velocity seems to be the biggest.
And this has a lot of sense, because while the distance between the values of time is constant (is always 100 seconds) we can see that the difference between consecutive values of y(t) is increasing.
Then we can conclude that the rocket is accelerating upwards, then as larger is the value of t, bigger will be the average velocity at that point.
Answer:
- 23
Step-by-step explanation:
We could do this the long way and expand the whole product or note that the 
terms arise from the product of the a³ and a terms and the product of the a² and a² terms, that is
4a³ × 3a = 12
+ 5a² × - 7a² = - 35
Summing gives
12 - 35 = - 23
with coefficient - 23
Answer:
Part A) 
Part B) She will spend more than 
Step-by-step explanation:
Let
p-----> the number of hamburger patties
Part A) Luna has to buy at least 16 packages for an upcoming picnic
Part B) Suppose she actually needs more than 150 hamburgers. How much will she spend?
Let
c---------> the total cost
step 1
Divide 150 hamburgers by 8 (a package of hamburgers)
so
round to the nearest whole number
----> the minimum number of packages
step 2
Answer:
C. (18+4)
Step-by-step explanation:
The answer on ed
Answer:D
Step-by-step explanation:
