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Ronch [10]
1 year ago
10

Find the area of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximati

ons). Will give brainliest!!!

Mathematics
1 answer:
Svetach [21]1 year ago
8 0

Answer:

Answer:18+4.5\pi \\

Step-by-step explanation:

This shape is a triangle with a semicircle connected to it

and this triangle is a right triangle so side A=B

that means the other leg is 6.Knowing that we can solve

The formula for the area of a triangle is (base×height)÷2

so that means 6×6 equals 36 and if you divide that by 2 you get the 18.

Now we will deal with the semicircle. We know that both of the legs are 6 so that means the diameter is 6 and now we solve 6 divided by 2 equals 3 and we will have to square that and we will 9 and since it is a semicircle we have to divide it by 2  and that will give us 4.5 and since we have to express it in terms of pi it will be 4.5(pi) and then we add both of the areas

giving us 18+4.5(pi)

and do you go to RSM

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Which test point holds true for y − 2x ≤ 1?
CaHeK987 [17]
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3 0
1 year ago
For each system of equations, drag the true statement about its solution set to the box under the system?
natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

 of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

   coefficients of x and y are the same and the numerical terms

   are the same

- The system of equation has one solution if at least one of the

  coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

  numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

3 0
2 years ago
(iii) Find the smallest whole number h such that<br>4704/h<br>is a cube number.<br>​
yan [13]

Answer:

h=588

Step-by-step explanation:

Given the fraction \dfrac{4,704}{h}

Consider its numerator and factor it:

4,704=2^5\cdot 3\cdot 7^2

You cann not take the cube root from 3, 7^2, 2^5, you can only take the cube root from 2^3, then the smallest whole number h such that \dfrac{4,704}{h} is a cube number is

h=2^2\cdot 3\cdot 7^2=4\cdot 3\cdot 49=588

When h=588,

\dfrac{4,704}{588}=8=2^3

6 0
1 year ago
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