A = FV - OV/T for OV
2 answers:
we have that
solve for OV
Multiply both sides by T
Add OV to both sides
Substract A*T both sides
simplify
therefore
the answer is
Solve for OV = T(FV-a)
<h3>Further explanation</h3>Sentences that have the same relationship are called equations
Linear equations are open sentences that have the same relationship with a variable and the exponent number is one
One variable linear equation is an equation that has a variable and the exponent number is one. Can be stated in the form:
ax = b or ax + b = c,
where
a, b, and c are constants, x is a variable
Whereas the two-variable linear equation is a linear equation that has 2 variables and the exponent is one
Can be stated in the form:
ax + by = c
x, y = variable
The solution of linear equations can be done by:
- 1. substitution, elimination
- 2. increase or decrease both segments with the same number
- 3. multiplying or dividing two segments with equal numbers
- 4. graph
In the task, it's known linear equations :
a = FV - OV/T
We will solve it using methods 2 and 3
- methode 3
multiplying the two segments by T, so it is expected that no fractions on both side :
aT= FVT - OV
- methode 2
we add both side with OV
aT + OV = FVT
we move aT to the right side, then we get OV
OV = FVT - aT
OV = T(FV-a)
<h3>Learn more </h3>Three times b less than 100
two-variable linear equations
James is two years younger
Keywords : one variable, linear equation, two variable, constants, y variable, x variable,exponent
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Answer:
TRUE OPTIONS ARE:
<em>"The temperature increased until 4:00 p.m. "</em>
<em>"The temperature decreased after 6:00 p.m. "</em>
<em>"The temperature increased more quickly between 12:00 p.m. and 4:00 p.m. than before 12:00 p.m."</em>
Step-by-step explanation:
<em>graph attached and complete question below:</em>
<em>Which statements are true about the temperatures Luis recorded on the graph? Check all that apply. </em>
- <em>The temperature increased until 4:00 p.m. </em>
- <em>The temperature was not recorded between 4:00 p.m. and 6:00 p.m. </em>
- <em>The temperature decreased after 6:00 p.m. </em>
- <em>The temperature increased and then decreased before holding constant. </em>
- <em>The temperature increased more quickly between 12:00 p.m. and 4:00 p.m. than before 12:00 p.m.</em>
<em />
Until 1600 hours, the graph increases, so we can say temperature increased until 4.00 pm (FIRST OPTION TRUE).
From 1600 to 1800 hours (4 - 6pm), the temperature stayed same (horizontal line). This doesn't mean the temperature wasn't recorded. (2nd OPTION FALSE).
After 1800 hours (6pm), the line goes downward, so temperature decreased after 6 pm. (3rd OPTION TRUE).
If you look at the temperature graph, we can see temperature increased, then increased more, then constant, then decreased. Thus the 4th option isnt true. (4th OPTION FALSE).
Before 12, the increase isn't as sharp as after 12. After 12 temperature increase has more slope, so this increase is more. (5th OPTION TRUE).
Let x represent number of bracelets and y represent number of necklaces.
We have been given that a jeweler made 7 more necklaces than bracelets. This means that number of necklaces will be . We can represent this information in an equation as:
We have been given that the amount of gold in each bracelet is 6 grams, so amount used for x bracelets would be grams.
We are also told that the amount of gold in each necklace is 16 grams, so amount used for y necklaces would be grams.
Since the jeweler used 178 grams of gold, so we will equate the amount of gold used in x bracelets and y necklaces with 178 as:
Therefore, our required system of equations would be: