we have that
solve for OV
Multiply both sides by T
Add OV to both sides
Substract A*T both sides
simplify
therefore
the answer is
Solve for OV = T(FV-a)
<h3>Further explanation</h3>Sentences that have the same relationship are called equations
Linear equations are open sentences that have the same relationship with a variable and the exponent number is one
One variable linear equation is an equation that has a variable and the exponent number is one. Can be stated in the form:
ax = b or ax + b = c,
where
a, b, and c are constants, x is a variable
Whereas the two-variable linear equation is a linear equation that has 2 variables and the exponent is one
Can be stated in the form:
ax + by = c
x, y = variable
The solution of linear equations can be done by:
In the task, it's known linear equations :
a = FV - OV/T
We will solve it using methods 2 and 3
multiplying the two segments by T, so it is expected that no fractions on both side :
aT= FVT - OV
we add both side with OV
aT + OV = FVT
we move aT to the right side, then we get OV
OV = FVT - aT
OV = T(FV-a)
<h3>Learn more </h3>Three times b less than 100
two-variable linear equations
James is two years younger
Keywords : one variable, linear equation, two variable, constants, y variable, x variable,exponent
It is given in the question that
Suppose the supply function for product x is given by
And we have to find how much of product x is produced when px = $600 and pz = $60.
And for that, we have to substitute 600 for px and 60 for pz, and on doing so, we will get
And that's the required answer .
Answer:
a: Sample mean: 20, Sample standard deviation: 1.732
b: 19.13 <µ < 20.87
c: 18.84< µ < 21.16
d: as the confidence level increases, the interval becomes wider
Step-by-step explanation:
a: Sample mean is found by adding up all the individual values of the sample, then dividing by the total number of values in the sample.
Sample standard deviation is the square root of the variance
See the first attached photo for the calculations of these values.
We need to create a 80% confidence interval for the population. Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.
Look for the column on the t-distribution chart that has "area in two tails" of 0.20 (80%), and row 7 (degree of freedom)
The t-value is 1.415
See the second attached photo for the construction of the confidence interval
We need to create a 90% confidence interval for the population. Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.
Look for the column on the t-distribution chart that has "area in two tails" of 0.10 (90%), and row 7 (degree of freedom)
The t-value is 1.895
See the third attached photo for the construction of the confidence interval
