Answer: b. 0.8413
Step-by-step explanation:
Given : The average time taken to complete an exam, X, follows a normal probability distribution with
and
.
Then, the probability that a randomly chosen student will take more than 30 minutes to complete the exam will be :-
[using z-value table]
Hence, the probability that a randomly chosen student will take more than 30 minutes to complete the exam = 0.8413
Answer:
The probability that the man is greater than 74 inches is 0.1587
Step-by-step explanation:
The required probability is found by evaluating the area under the corresponding distribution curve for the corresponding values
The standard normal variate factor (Z) is given by

where
is mean of the data
is the standard deviation of the data
Thus corresponding to x = 74 the Z factor equals

Using the standard normal distribution table corresponding to mean of 70 and deviation of 4 the area under the curve corresponding to Z = 1 equals
0.1587
Answer:
21
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given a sample M(t)
M(t) = 120 • ( 81 / 625)^t
When is the fraction of the mass decay to 3/5 of it's mass
Generally
M(t) = Mo•(k^t)
The original mass is 120
Mo = 120
So, we want to find time when it decay to 3/5 of it's original mas
M = 3/5 × 120
M = 72
Then,
M(t) = 120 • ( 81 / 625)^t
72 = 120 • ( 81 / 625)^t
72 / 120 = ( 81 / 625)^t
0.6 = ( 81 / 625)^t
Take natural logarithmic of both sides
In(0.6) = In(81/625)^t
In(0.6) = t•In(81/625)
t = In(0.6) / In(81/625)
t = In(0.6) / In(0.1296)
t = 0.25 monthly
t = ¼ monthly