Answer:
(A) 0.15625
(B) 0.1875
(C) Can't be computed
Step-by-step explanation:
We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.
Let X = Amount of time taken by student to complete a statistics quiz
So, X ~ U(32 , 64)
The PDF of uniform distribution is given by;
f(X) =
, a < X < b where a = 32 and b = 64
The CDF of Uniform distribution is P(X <= x) =
(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)
P(X > 59) = 1 - P(X <= 59) = 1 -
= 1 -
=
= 0.15625
(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43) = P(X <= 43) - P(X < 37)
P(X <= 43) =
=
= 0.34375
P(X < 37) =
=
= 0.15625
P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875
(C) Probability that student complete the quiz in exactly 44.74 minutes
= P(X = 44.74)
The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.
Remember, rise/run is the easiest way to determine slope
y=mx+b is form
mx is slope, whilst b is y int
so, answer? y=-3x-2
Or A.
Given that a is an integer from -22 to 0 such that a is equivalent to 43 (mod 23).
Such a can be obtained as follows:
a = 43 (mod 23) - 23 = 20 - 23 = -3.
Therefore, a = -3.
Answer:
$(8967/n + 8.4)
Step-by-step explanation:
0.4nx + 0.6n(x+21) = 8967
nx + 12.6n = 8967
x = 8967/n - 12.6
x+21 = 8967/n + 8.4
Where n is the no. of balls
Example: if total balls were 300
n = 300
More expensive one would cost:
8967/300 + 8.4 = $38.29
Answer:
0.38% probability that the sample contains exactly two defective parts.
Step-by-step explanation:
For each part, there are only two possible outcomes. Either it is defective, or it is not. The probabilities for each part being defective are independent from each other. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem we have that:

What is the probability that the sample contains exactly two defective parts?
This is 


0.38% probability that the sample contains exactly two defective parts.