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Harman [31]
2 years ago
6

You have just opened a new dance club, Swing Haven, but are unsure of how high to set the cover charge (entrance fee). One week

you charged $4 per guest and averaged 80 guests per night. The next week you charged $10 per guest and averaged 44 guests per night. (a) Find a linear demand equation showing the number of guests q per night as a function of the cover charge p.
Mathematics
1 answer:
aliya0001 [1]2 years ago
7 0

Answer:

q = -6p + 104

Step-by-step explanation:

Linear function:

A linear function has the following format:

q = mp + b

In which m is the slope and b is the q-intercept.

One week you charged $4 per guest and averaged 80 guests per night. The next week you charged $10 per guest and averaged 44 guests per night.

This means that we have these following points: (4,80), (10,44).

Finding the slope:

With a pair of points, the slope is given by the change in q divided by the change in p.

Change in q: 44 - 80 = -36

Change in p: 10 - 4 = 6

Slope: m = \frac{-36}{6} = -6

So

q = -6p + b

Finding b:

We replace one of the points. Replacing (4,80).

q = -6p + b

80 = -6*4 + b

b = 104

So

q = -6p + 104

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The amount of time it takes for a student to complete a statistics quiz is uniformly distributed (or, given by a random variable
topjm [15]

Answer:

(A) 0.15625

(B) 0.1875

(C) Can't be computed

Step-by-step explanation:

We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.

Let X = Amount of time taken by student to complete a statistics quiz

So,   X ~ U(32 , 64)

The PDF of uniform distribution is given by;

    f(X) = \frac{1}{b-a} ,  a < X < b      where a = 32 and b = 64

The CDF of Uniform distribution is P(X <= x) = \frac{x-a}{b-a}

(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)

   P(X > 59) = 1 - P(X <= 59) = 1 - \frac{x-a}{b-a} = 1 - \frac{59-32}{64-32} = 1-\frac{27}{32} = 0.15625

(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43)  = P(X <= 43) - P(X < 37)

    P(X <= 43) = \frac{43-32}{64-32} = \frac{11}{32} = 0.34375

    P(X < 37) = \frac{37-32}{64-32} = \frac{5}{32} = 0.15625

    P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875

(C) Probability that student complete the quiz in exactly 44.74 minutes

     = P(X = 44.74)

The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.

3 0
2 years ago
Which linear equation represents on the graph
s2008m [1.1K]

Remember, rise/run is the easiest way to determine slope

y=mx+b is form

mx is slope, whilst b is y int

so, answer? y=-3x-2

Or A.

4 0
2 years ago
Find the integer a such that<br> a.a ≡ 43 (mod 23) and −22 ≤ a ≤ 0.
Margaret [11]
Given that a is an integer from -22 to 0 such that a is equivalent to 43 (mod 23).

Such a can be obtained as follows:

a = 43 (mod 23) - 23 = 20 - 23 = -3.

Therefore, a = -3.
8 0
2 years ago
The basketballs Noah packed had two different prices. Of the total number of basketballs sold, 60% had a price that was $21 more
kirill115 [55]

Answer:

$(8967/n + 8.4)

Step-by-step explanation:

0.4nx + 0.6n(x+21) = 8967

nx + 12.6n = 8967

x = 8967/n - 12.6

x+21 = 8967/n + 8.4

Where n is the no. of balls

Example: if total balls were 300

n = 300

More expensive one would cost:

8967/300 + 8.4 = $38.29

8 0
2 years ago
Assuming a binomial distribution, a production process produces 2% defective parts. A sample of five parts from the production p
Murrr4er [49]

Answer:

0.38% probability that the sample contains exactly two defective parts.

Step-by-step explanation:

For each part, there are only two possible outcomes. Either it is defective, or it is not. The probabilities for each part being defective are independent from each other. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 5, p = 0.02

What is the probability that the sample contains exactly two defective parts?

This is P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{5,2}.(0.02)^{2}.(0.98)^{3} = 0.0038

0.38% probability that the sample contains exactly two defective parts.

3 0
2 years ago
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