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Sveta_85 [38]
2 years ago
11

Let #N mean the number of days in year N. What is the value of #1988 + #1989 + #1990 + #1991?

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
6 0

Answer:

I need help though cause I had this for homework right now

Step-by-step explanation:

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A recent survey of 8,000 high school students found that the mean price of a prom dress was $195.00 with a standard deviation of
beks73 [17]
H0= 195; Ha > 195
Hope this helps.
8 0
2 years ago
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The table below shows how much Joe earns, y, after working x hours.
allochka39001 [22]
Both slopes have the same value which is 7.5.

To compute for the slope we will use this formula:
   m = y^2 - y^1 over x^2 - x^1

For the first slope, the points are<span> (4, 30) and (12, 90). Substitute and simplify.
   m = (90 - 30) over (12 - 4)
   m = 7.5

For the second slope, the points are </span><span>(4, 30) and (10, 75). Same with the above computation.
   m = (75 - 30) over (10 - 4)
   m = 7.5

Since the relationship is linear, the slope does not change. </span>
6 0
2 years ago
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The number of pages in the U.S. tax code exceeds the number of pages in the King James Bible by 18,528. The combined number of p
xeze [42]
Let the pages in U.S. Tax code be x pages while those in King James Bible be y pages.

From the information give,
x= y+18,528 => y=x-18,528
x+y = 21,472 => x+(x-18,528) = 21,472 => x+x-18,528 = 21,472 => 2x= 18,528+21,472 => 2x = 40,000 => x=40,000/2 = 20,000 pages

Therefore, U.S. tax code has 20,000 pages.
6 0
2 years ago
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a rectangular field is 20m long and 15m wide.there is a path of uniform width all around it having an area of 450m^2.find the wi
myrzilka [38]

Answer:

22.5m

Step-by-step explanation:

450m²÷20m=22.5m

8 0
1 year ago
Elyria Warehousing desired to locate a central warehouse to serve five Ohio markets. Placed on a grid system, its five markets h
Iteru [2.4K]

Answer:

The correct option is 2.

Step-by-step explanation:

According to the the center-of-gravity technique, the coordinates of the center-of-gravity location are

(\frac{\sum x_iL_i}{\sum L_i},\frac{\sum y_iL_i}{\sum L_i})

Where ((x_i,y_i) represent the coordinates and L_i is demand.

We have to find the Y-coordinate of the center-of-gravity location.

The sum of product of demand and corresponding y coordinates is

\sum y_iL_i=65\times 2200+55\times 900+95\times 1300+200\times 1750+175\times 3100=1208500

The sum of demanded units is

\sum L_i=2200+900+1300+1750+3100=9250

The Y-coordinate of the center-of-gravity location is

y_0=\frac{\sum y_iL_i}{\sum L_i}

y_0=\frac{1208500}{9250}

y_0=130.6486

y_0\approx 131

The Y-coordinate of the center-of-gravity location is 131. Therefore the correct option is 2.

7 0
2 years ago
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