We can used the Simpson's Rule says to approximate the area under a given curve using the following formula:
<span>(Δx/3)[f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + ... + 2f(xn-2) + 4f(xn-1) + f(xn)] </span>
<span>The pool is divided into 8 subintervals. We integrate the given function from 0 to 24, while the graph provides values of f(x) at 7 different points. The first value given, 6.2, is NOT f(0). It is f(3). Using Simpson's Rule, and dividing the lake of 24 meters into 8 subintervals, we write the equation: </span>
<span>area = (3/3)[f(0) + 4f(3) + 2f(6) + 4f(9) +2f(12) + 4f(15) + 2f(18) + 4f(21) + f(24)] </span>
<span>Pool area = 0 + 4(6.2) + 2(7.2) +4(6.8) + 2(5.6) + 4(5.0) +2(4.8) +4(4.8) + 0 = 126.4 m^2 </span>
<span>Rounding to the nearest square meter, the area of the lake is approximately 126 m^2 </span>
So for number there are 6 possible outcomes nad 5 is one of them so 1/6
He next one there are 2 outcomes and heads is 1 outcome so 1/2
For the next one you have to multiply them together so you get 1/12
And the events are independent because whatever you roll on the die won’t affect the coin(it actually does on a very small scale but I don’t think you go into that much detail for high school maths)
