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Arisa [49]
2 years ago
6

Consider the following equivalent expressions: 38÷1312 and 38⋅ab. What are the values of a and b? Give the value of a followed b

y the value of b, separated by a comma. The value of a and the value of b should be the smallest possible non-negative whole number for each. nothing
Mathematics
1 answer:
yKpoI14uk [10]2 years ago
7 0

Answer:

The values of a and b are {12,13}

Step-by-step explanation:

As,

\frac{\frac{3}{8}}{\frac{13}{12}}=\frac{3}{8}\frac{a}{b}

We convert the division into a multiplication by inverting the denominator

\frac{3}{8}}\frac{12}{13}=\frac{3}{8}\frac{a}{b}

Therefore, the smallest possible non-negative whole numbers for a and b could be are 12 and 13, respectively.

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If 2x2 + y2 = 17 then evaluate the second derivative of y with respect to x when x = 2 and y = 3. Round your answer to 2 decimal
Vera_Pavlovna [14]

Answer:

y''=-1.26

Step-by-step explanation:

We are given that 2x^2+y^2=17

We have evaluate the second order derivative of y w.r.t. x when x=2 and y=3.

Differentiate w.r.t x

Then , we get

4x+2yy'=0

2x+yy'=0

yy'=-2x

y'=-\frac{2x}{y}

Again differentiate w.r.t.x

Then , we get

2+(y')^2+yy''=0 (u\cdot v)'=u'v+v'u)

2+(y')^2+yy''=0

Using value of y'

yy''=-2-(-\frac{2x}{y})^2

y''=-\frac{2+(-\frac{2x}{y})^2}{y}

Substitute x=2 and y=3

Then, we get y''=-\frac{2+(\frac{4}{3})^2}{3}

y''=-\frac{18+16}{9\times 3}=-\frac{34}{27}

Hence,y''=-1.26

6 0
2 years ago
Royce has $15 with him and spends $12 to buy his favorite comics. He has $3 left, which he deposits in the bank. Which number wi
Damm [24]
The value 3 will be entered. It's a positive value to indicate he is not in debt of any kind. 
7 0
2 years ago
The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.410.410, point, 4 years; th
kati45 [8]

Answer:

99.85%

Step-by-step explanation:

The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.4 years; the standard deviation is 1.9 years.

Use the empirical rule (68-95-99.7%) to estimate the probability of a meerkat living less than 16.1 years.

Solution:

The empirical rule states that for a normal distribution most of the data fall within three standard deviations (σ) of the mean (µ). That is  68% of the data falls within the first standard deviation (µ ± σ), 95% falls within the first two standard deviations (µ ± 2σ), and 99.7%  falls within the first three standard deviations (µ ± 3σ).

Therefore:

68% falls within (10.4 ± 1.9). 68% falls within 8.5 years to 12.3 years

95% falls within (10.4 ± 2*1.9). 95% falls within 6.6 years to 14.2 years

99.7% falls within (10.4 ± 3*1.9). 68% falls within 4.7 years to 16.1 years

Probability of a meerkat living less than 16.1 years = 100% - (100% - 99.7%)/2 = 100% - 0.15% = 99.85%

7 0
1 year ago
Read 2 more answers
In the diagram, DC is 10 units and BC is 6 units. Line l is a perpendicular bisector of line segment A C. It intersects line seg
Orlov [11]

Answer:

  12 units

Step-by-step explanation:

Point B is the midpoint of AC, and it is 6 units from C. Therefore A must be 12 units from C.

  AC = 12 units

7 0
2 years ago
Read 2 more answers
Tan 235° = 2tan20°+ tan215°​
Mariulka [41]

Given :  tan 235 = 2 tan 20 + tan 215

To Find : prove that

Solution:

tan 235 = 2 tan 20 + tan 215

Tan x = Tan (180 + x)

tan 235 = tan ( 180 + 55) = tan55

tan 215 = tan (180 + 35) = tan 35

=> tan 55 = 2tan 20 + tan 35

55 = 20 + 35

=> 20  = 55 - 35

taking Tan both sides

=> Tan 20 = Tan ( 55 - 35)

=> Tan 20  = (Tan55 - Tan35) /(1 + Tan55 . Tan35)

Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1

=> Tan 20  = (Tan 55 - Tan 35) /(1 + 1)

=> Tan 20  = (Tan 55 - Tan 35) /2

=> 2 Tan 20  = Tan 55 - Tan 35

=> 2 Tan 20 +  Tan 35 = Tan 55

=>  tan 55 = 2tan 20 + tan 35

=>  tan 235 = 2tan 20 + tan 215

QED

Hence Proved

5 0
2 years ago
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