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Mkey [24]
2 years ago
13

Now evaluate f(x) = 2x4 - 4x3-11x2+3x-6 for x=-2 f (-2) =

Mathematics
2 answers:
PtichkaEL [24]2 years ago
7 0

Answer:

The answer is 8.

Step-by-step explanation:

bija089 [108]2 years ago
4 0
f(x)=2x^4-4x^3-11x^2+3x-6\\\\f(-2)=2\cdot(-2)^4-4\cdot(-2)^3-11\cdot(-2)^2+3\cdot(-2)-6\\\\f(-2)=2\cdot16-4\cdot(-8)-11\cdot4+3\cdot(-2)-6\\\\f(-2)=32+32-44-6-6=8
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Weiming, Farhan and Sam had some comic books.
mixas84 [53]

Answer:

Farhan had 9 comic books

Sam had 51 comic books and lived in his Mother's basement

Step-by-step explanation:

W + F = 36

W = 3F

3F + F = 36

F = 9

W = 27

S + F = 60

S + 9 = 60

S = 51

5 0
1 year ago
I increase a number by 24% the answer is 6014 what number did I start with
miskamm [114]

Answer:

1443.36

Step-by-step explanation:

6014*.24=1443.36

Hope it helps

8 0
1 year ago
Alexis put $2000 in a savings account. After 4 years, she had $2543 in the account. What rate of interest did she earn? Use the
Flauer [41]
This is substitution, it's very simple once you get the hang of it! 

okay, what you want to do is plug in the numbers you already have, to get the number you don't have(r).

First, you plug in the numbers.

1.  P= $2000  
    A=$2543
    t= 4(years)
    r=? 

2543=2000^r(4) 

Secondly, you want to solve the equation.


5 0
2 years ago
Read 2 more answers
give an example on an addition problem in which you would and would not group the addends differently to add
Murrr4er [49]
Addends are any of the numbers added together in an equation. 

The only time their grouping would matter would be if there were parentheses used to alter the normal Order of Operations. 

For ex:
2 - (8 + 3)  here, the 8 and 3 have to be grouped together before doing the subtraction.

Any addition problem without parentheses can be used for one where the grouping doesn't matter
3 0
2 years ago
the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev
Naya [18.7K]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 16}{2.1}

Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

4 0
2 years ago
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