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Mkey [24]
2 years ago
13

Now evaluate f(x) = 2x4 - 4x3-11x2+3x-6 for x=-2 f (-2) =

Mathematics
2 answers:
PtichkaEL [24]2 years ago
7 0

Answer:

The answer is 8.

Step-by-step explanation:

bija089 [108]2 years ago
4 0
f(x)=2x^4-4x^3-11x^2+3x-6\\\\f(-2)=2\cdot(-2)^4-4\cdot(-2)^3-11\cdot(-2)^2+3\cdot(-2)-6\\\\f(-2)=2\cdot16-4\cdot(-8)-11\cdot4+3\cdot(-2)-6\\\\f(-2)=32+32-44-6-6=8
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2.314 divided by 1.3
kirza4 [7]
1.78 is the correct answer.
5 0
2 years ago
The vertices of △ DEF are D (2, 5), E (6, 3), and F (4, 0). Translate △ DEF using the given vector. Graph △ DEF and its image. T
jeyben [28]

Answer:

The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

Step-by-step explanation:

Given the vertices of △ DEF are D (2, 5), E (6, 3), and F (4, 0). We have to translate the triangle using the vector (6, 0)

Now, translation by vector (6, 0)

D (2, 5)=D'(2+6, 5+0)=D'(8, 5)

E (6, 3)=E'(6+6, 3+0)=E'(12, 3)

F (4, 0)=F'(4+6, 0+0)=F'(10,0)

Now, we have to label the coordinate of the triangle or to get image of triangle after translation.

Hence, The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

7 0
1 year ago
A cylinder and a cone have the same base and height. The cylinder can hold about 4,712 Centimeters cubed of sand. Jared says tha
o-na [289]

Answer:

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

The formula for determining the volume of a cone is expressed as

Volume = 1/3πr²h

This means that the volume of a cone is 1/3 × volume of a cylinder if they have the same base and height.

If the cylinder can hold about 4,712 Centimeters cubed of sand and Jared says that the cone can hold about 1,178 Centimeters cubed of sand, then

Jared is not correct because the cone and the cylinder have the same base and height so the cone holds StartFraction 4,712 Over 3 EndFraction almost-equals 1,571 centimeters cubed of sand.

6 0
1 year ago
Solve the given initial value problem and determine how the interval in which the solution exists depends on the initial value y
zalisa [80]

Answer:

y has a finite solution for any value y_0 ≠ 0.

Step-by-step explanation:

Given the differential equation

y' + y³ = 0

We can rewrite this as

dy/dx + y³ = 0

Multiplying through by dx

dy + y³dx = 0

Divide through by y³, we have

dy/y³ + dx = 0

dy/y³ = -dx

Integrating both sides

-1/(2y²) = - x + c

Multiplying through by -1, we have

1/(2y²) = x + C (Where C = -c)

Applying the initial condition y(0) = y_0, put x = 0, and y = y_0

1/(2y_0²) = 0 + C

C = 1/(2y_0²)

So

1/(2y²) = x + 1/(2y_0²)

2y² = 1/[x + 1/(2y_0²)]

y² = 1/[2x + 1/(y_0²)]

y = 1/[2x + 1/(y_0²)]½

This is the required solution to the initial value problem.

The interval of the solution depends on the value of y_0. There are infinitely many solutions for y_0 assumes a real number.

For y_0 = 0, the solution has an expression 1/0, which makes the solution infinite.

With this, y has a finite solution for any value y_0 ≠ 0.

8 0
2 years ago
If a conditional statement is “If the sun shines, people will be in good moods”, what is the statement “If the sun does not shin
77julia77 [94]

Answer:

C. Inverse

Step-by-step explanation:

The second statement is the inverse, because in an inverse, the hypothesis and the conclusion are both negated. In this case, the sun doesnt shine and the people wont be in a good mood, as opposed to the sun will shine, and the people will  be in a good mood.

7 0
1 year ago
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