2.314 divided by 1.3
1 answer:
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<u>ANSWER</u>
<u>EXPLANATION</u>
The given compound inequality is
We need to simplify this inequality so that we can obtain x standing alone between the inequality signs.
We add 6 through out the inequality.
This simplifies to:
We now divide through by -3 and reverse the inequality sign.
We now simplify to get:
Answer:
A cone with base radius of 17 in
Step-by-step explanation:
Given
Triangle ABC
Where
AB = BC = 24in
D = Midpoint of AC
Required
Which best describes the resulting three-dimensional figure?
First, the length of the third side of the triangle has to be calculated
The sides of triangle ABC are AB, AC and BC
Given that the perimeter = 82 in
AB + AC + BC = 82
Recall that AB = BC = 24in; The equation becomes
Collect like terms
Given that, the triangle is rotated at D, the midpoint of AC
The length of the midpoint has to be calculated
At this point, we can dismiss options C and D.
This is because; a triangular pyramid is formed by more than 1 triangles (at least 3 triangle) and in this case, we're dealing with only 1 triangle.
So, we have option A and B to select from.
When the triangle is rotated at point D, it generates a cone such that the radius of the cone is the distance at point D.
This implies that, a cone with base radius D is generated.
Recall that D = 17.
Hence, <em>A cone with base radius of 17 in</em>
Answer:
The answer is "$ 11,961.43"
Step-by-step explanation:
Given values:
P = $ 9500
r= 2.1 %
time (t)= 11 year
total quarterly year =4
Formula:
quarterly time =
Answer: We can arrange the steps with help of below explanation.
Step-by-step explanation:
Here ABC is a triangle,
Draw a perpendicular from BD to side AC ( construction)
where
In the right triangle BCD, from the definition of cosine:
cos C =CD/ BC
CD= a cos C
Subtracting this from the side b, we see that
DA= b-acos C
In the triangle BCD, from the definition of sine:
sin C =BD / a
BD = a sin C
In the triangle ADB, applying the Pythagorean Theorem
Substituting for BD and DA from (2) and (3)
⇒ ( On simplification)
⇒
⇒
⇒ (because,
)
