The smallest number of tiles Quintin will need in order to tile his floor is 20
The given parameters;
- number of different shapes of tiles available = 3
- area of each square shape tiles, A = 2000 cm²
- length of the floor, L = 10 m = 1000 cm
- width of the floor, W = 6 m = 600 cm
To find:
- the smallest number of tiles Quintin will need in order to tile his floor
Among the three different shapes available, total area of one is calculated as;
Area of the floor is calculated as;
The maximum number tiles needed (this will be possible if only one shape type is used)
When all the three different shape types are used we can get the smallest number of tiles needed.
The minimum or smallest number of tiles needed (this will be possible if all the 3 different shapes are used)
Thus, the smallest number of tiles Quintin will need in order to tile his floor is 20
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Answer:
20n² - 40n + 20
Step-by-step explanation:
(5n - 5)(4n - 4)
= 5n(4n) + 5n(-4) - 5(4n) - 5(-4)
= 20n² - 20n - 20n + 20
= 20n² - 40n + 20
Another way to do this:
(5n - 5)(4n - 4)
= 5(n - 1) * 4(n - 1)
= 20(n - 1)(n - 1)
= 20(n - 1)²
= 20(n² - 2n + 1)
= 20n² - 40n + 20
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Starting population = 4000
Addition per month = 170
decline on population per month = 70
Increase rate in population per month (dt) :
Starting population = 4000
Number of births per month = 170
However, the population declines by 70 individuals each month
Hence,
Number of births - number of deaths(d) = 70
170 - d = - 70 ( decline?
170 + 70 = d
240 = d
d = number of deaths
Per capita death :
Total number of deaths per. Month / starting population
= 240 / 4000
= 0.06
A(bx − c) ≥ bc, implies (bx − c) ≥ bc /a and then bx ≥ bc/a + c, x<span>≥ c/a +c/b
so the solution is </span><span>3. [c/a + c/b, infinity)</span>
Answer:
The number line is missing, but as we are know that the number marked in the number line is -6/4, i will guess that the ticks are spearated by fourts (the distance between each tick is 1/4).
Now, for the number at the right of -6/4, we should add the distance for one tick, this means that the number at the right is:
-6/4 + 1/4 = -5/4.
Now i will give some other examples:
Now, if the distance between ticks is 2/4, then the number at the right will be:
-6/4 + 2/4 = -4/4 = -1
Now, if the distance between ticks is 3/4, the the number at the right will be:
-6/4 + 3/4 = -3/4.
