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jasenka [17]
2 years ago
10

The polygons below are similar. Find the value of y. (2 points)

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
8 0

Answer:

the answer is A(4.5)

Step-by-step explanation:

y/6 = 6/8

y=9/2 = 4.5

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I) Solve the equation sin2x + 3cos2x = 0 (for 0 till 360°)
galina1969 [7]
Get rid of cos2x by dividing both the values. So Sin2x/cos2x +3cos2x/cos2x.
Tan2x = 3
2x = -71.5 so x is -35.6
Use the quadrant method and add 360 twho the two values tou get.
7 0
2 years ago
Solve 3x2 + 18x + 15 = 0 by completing the square. 3(x + 3)2 = 6; x = −3 + square root 2, x = −3 − square root 2 3(x + 9)2 = 12;
Damm [24]
3(x + 3)2 = 12; x = -5, x = -1
5 0
2 years ago
Read 2 more answers
a teacher needs 70 lengths of string cut to 40 cm each. If balls of string are 10 m long how many balls will be needed
LenKa [72]
A meter is 100 cm. A ball of string has 10m of string, and you multiply 10m by 100cm, you get 1,000cm. Then you multiply 40cm by 2, and you get 80cm, or two lengths of string. Then you multiply 35, which is half of 70, by 80, and that is 2,800 cm.
2,800
÷40cm=70
And 100cm=1m.
The teacher will therefore need 28 balls of string.
7 0
2 years ago
Two identical decks of 52 cards are mixed together, yielding a stack of 104 cards. How many different ways are there to order th
kumpel [21]

Answer:

here the order will be 104! =1.029e^{166}

Step-by-step explanation:

since the cards are to arranged in  no particular order that is why we used combination to find the result.

Combination can simply be explained as the method of selecting items from a collection of items where the order of the selections does not matter.

7 0
2 years ago
Suppose r(t)= cos(t)i+sin(t)j+(2t)k represents the position of a particle on a helix, where Z is the height of the particle abov
Gwar [14]

Answer:

The parametric equations for the tangent line are :

x = Cos(10) - t×Sin(10)

y = Sin(10) + t×Cos(10)

z = 20 + 2t

Step-by-step explanation:

When Z=20:

Z=2t=20 ⇒ t=10

The point of tangency is:

r(10)= Cos(10) i + Sin(10) j + 20 k

We have to find the derivative of r(t) to get the tangent line:

r'(t)= -Sin(t) i + Cos(t) j + 2 k

The direction vector at t=10 is:

r'(10)= -Sin(10) i + Cos(10) j + 2 k

So, the equation of the tangent line is given by:

x = cos 10 -t×Sin(10)

y = sin 10 + t×Cos(10)

z = 20 + 2t

4 0
2 years ago
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