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2 years ago

What is the surface area of the right cone below?

Mathematics

1 answer:

maksim [4K]2 years ago

6 0

Answer:

$SA=54\pi\ units^2$

Step-by-step explanation:

we know that

The surface area of the cone is given by the formula

$SA=\pi r^{2}+\pi rl$

where

r is the radius of the base

l is the slant height

we have

$r=3\ units\\l=15\ units$

substitute

$SA=\pi (3)^{2}+\pi (3)(15)$

$SA=54\pi\ units^2$

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Which would prove that ΔABC ~ ΔXYZ? Select TWO options.

gulaghasi [49]

Answer:

$\frac{BA}{YX}=\frac{BC}{YZ}$ , ∠C ≅∠Z

$\frac{AC}{XZ}=\frac{BA}{YX}$ , ∠A≅∠X

$\frac{BA}{YX}=\frac{BC}{YZ}=\frac{AC}{XZ}$

Step-by-step explanation:

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

The corresponding sides are

BA and YX

BC and YZ

AC and XZ

The corresponding angles are

∠A and ∠X

∠B and ∠Y

∠C and ∠Z

$\frac{BA}{YX}=\frac{BC}{YZ}=\frac{AC}{XZ}$

and

∠A≅∠X

∠B≅∠Y

∠C ≅∠Z

therefore

$\frac{BA}{YX}=\frac{BC}{YZ}$ , ∠C ≅∠Z

$\frac{AC}{XZ}=\frac{BA}{YX}$ , ∠A≅∠X

$\frac{BA}{YX}=\frac{BC}{YZ}=\frac{AC}{XZ}$

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Answer:

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Step-by-step explanation:

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Answer:

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