Answer:
Step-by-step explanation:
find the attached below
V=hpir^2
r=2
h=5
pi≈3.141592
v=5*3.141592*2^2
v=5*3.141592*4
v=20*3.141592
v=62.83185307179586476925286766559
round to tenth
62.8 cubic units
Answer: y = -9
Step-by-step explanation:
(-2y) + y - 3 = 6
(-y) - 3 = 6
-y = 9
y = -9
Answer/Step-by-step explanation (ac > b² or b² < ac.
)
A/c to question, we have to show:-
b² >ac in A.P ........ (1)
b² = ac in G.P .....(2)
b² < ac in H.P. ..... (3)
b = a+c/2 (A.P)
b = √ac ( G.P)
b = 2ac/a+c (H.P)
In A.P :
b² > ac = b² - ac
= (a+c/2)² - ac
= (a²+2ac+c²/4) - ac = a² + 2ac + c² - 4ac / 4
= a² - 2ac + c² / 4 = ( a - c ) ² / 4 > 0 Hence, b²>ac
In G.P:-
b = √ac
Hence, b² = ac
In H.P :- b² < ac = ac > b² = ac - b² = ac - ( 2ac / a+c)
= ac(a+c) - 2ac / a+c
= a²c + ac² - 2ac / a+c
= ac(2ac - 2) / a+c > 0
Hence, ac > b² or b² < ac.
