A ladder 25 feet long is leaning against the wall of a building. Initially, the foot of the ladder is 7 feet from the wall. The
foot of the ladder begins to slide at a rate of 2 ft/sec, causing the top of the ladder to slide down the wall. The location of the foot of the ladder at time t seconds is given by the parametric equations (7 +2t, 0). The location of the top of the ladder will be given by parametric equations (0, y(t)). The formula for y(t)=√[625−(7+2t)²]. The domain of t values for y(t) ranges from 0 to 9.
Calculate the average velocity of the top of the ladder on each of these time intervals (correct to three decimal places):
a) [0,2]
b) [2,4]
c) [6,8]
d) [8,9]
Calculate the average velocity of the top of the ladder on each of these time intervals (correct to three decimal places):
a) [0,2]
b) [2,4]
c) [6,8]
d) [8,9]
1 answer:
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Given:
On the first day, she drove 650 miles in 10 hours.
On the second day, she got a later start and drove 540 miles in 8 hours.
To find:
Difference between average speed of second day and first day.
Solution:
We know that,
On the first day, she drove 650 miles in 10 hours. So, the average speed is
So, the average speed on first day is 65 miles per hour.
On the second day, she got a later start and drove 540 miles in 8 hours.
So, the average speed on second day is 67.5 miles per hour.
Difference between average speed is
Therefore, the average speed on the second day is 2.5 miles per hour is faster than first day.
Answer:
a) 6
Step-by-step explanation:
Expanding the polynomial using the formula:
Also
I think you mean
We can deduce that this term will be located somewhere in the middle. So I will calculate .
For
Note that we actually don't need to do all this process. There's no necessity to calculate the binomial, just
For