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lbvjy [14]
1 year ago
13

The vertices of △ DEF are D (2, 5), E (6, 3), and F (4, 0). Translate △ DEF using the given vector. Graph △ DEF and its image. T

he vector is (6, 0). Please help!

Mathematics
1 answer:
jeyben [28]1 year ago
7 0

Answer:

The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

Step-by-step explanation:

Given the vertices of △ DEF are D (2, 5), E (6, 3), and F (4, 0). We have to translate the triangle using the vector (6, 0)

Now, translation by vector (6, 0)

D (2, 5)=D'(2+6, 5+0)=D'(8, 5)

E (6, 3)=E'(6+6, 3+0)=E'(12, 3)

F (4, 0)=F'(4+6, 0+0)=F'(10,0)

Now, we have to label the coordinate of the triangle or to get image of triangle after translation.

Hence, The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

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In a normally distributed data set a mean of 55 where 95% of the data fall between 47.4 and 62.6, what would be the standard dev
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Answer:

The standard deviation of that data set is 3.8

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

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95% of the data fall between 47.4 and 62.6. This means that 47.4 is 2 standard deviations below the mean and 62.6 is two standard deviations above the mean.

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6 0
1 year ago
Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =
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Answer:

Here is the question attached with.

m\angle CEA =90 \ (deg)

m\angle BEF=135\ (deg)

\angle CEF is a straight line.

\angle AEF is a right angled triangle.

Options 1,4,5,6 are correct answers.

Step-by-step explanation:

⇒As \ ray\ AE  is ⊥FEC so it will forms right angled triangle then m\angle CEA =90\ (deg).

⇒Measure of \angle BEF =135\ (deg) as \angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg) as \angle AEB is the bisector of \angle AEC,meaning that  \angle AEB is half of \angle AEC so  \angle AEB = 45\ (deg).

⇒\angle CEF is a straight line as the angles measure over it is 180\ (deg).

⇒Measure of \angle AEF = 90\ (deg) from linear pair concept.

As \angle CEA + \angle AEF = 180\ (deg),plugging the values of  m\angle CEA =90\ (deg) we have \angle AEF = 90\ (deg) .

The other two options are false as:

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       it is exceeding 180\ (deg) whereas \angle CEF is a              

      straight line.

  • And m\angle CEB=2(m\angle CEA) is not true.

     As \angle CEA = 90\ (deg) and \angle CEB=45\ (deg)

So we have total 4 answers.

The correct options are 1,4,5,6.

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