The greatest common factor, or GCF, is the greatest factor
that divides two numbers. To find the GCF of two expression
<span>1.
</span>List the prime factors of each number.
<span>2.
</span>Multiply those factors both numbers
have in common. If there are no common prime factors, the GCF is 1.
16x^4y^3 = ( 4*4)(x*x*x*x)(y*y*y)
12x^2y^7 = (4*3)(x*x)(y*y*y*y*y*y*y)
<span>So common to them is 4x^2y^3 </span>
1. RM = SN, TM = TN Addition Property of Equality
2. ∠T = ∠T Reflexive
3. RM + TM = SN + TN Substitution
4. RM + TM = RT, SN + TN = ST Betweeness
5. RT = ST CPCTE
6. Triangle RTN congruent to Triangle STM Given
7. RN = SM SAS
First we find the area 10 x 21 = 210 then we multiply 210 x .70 and we get 147.00 total cost. d. 147.00
Answer:
a) 1 tsp.
b) 1.5 tsp.
c) 2 tsp.
Step-by-step explanation:
Complete Correct Question
Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a) a 18 kg adult dog (b) a 6 kg cat (c) 18 kg pregnant dog
- The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.
- The dosage listed for adult cat is 1/4 tsp per 1 kg weight.
- The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.
Solution
a) 18 kg adult dog
The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.
9 kg dog weight = (1/2) tsp
18 kg adult dog = (18/9) × (1/2) = 1 teaspoon.
b) 6 kg cat
The dosage listed for adult cat is 1/4 tsp per 1 kg weight.
1 kg cat = (1/4) tsp
6 kg cat = (6/1) × (1/4) = (6/4) = 1.5 teaspoons.
c) 18 kg pregnant dog
The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.
4.5 kg dog weight = (1/2) tsp
18 kg pregnant dog = (18/4.5) × (1/2) = 2 teaspoons.
Hope this Helps!!!
Divide total miles by speed to get how long it will take to drive:
569 miles / 65 mi/h = 8.75 hours.
Now subtract the time it takes to drive from the total time you can travel:
9.5 hours - 8.75 hours = 0.75 hours.
You can stop for 0.75 hours.
