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2 years ago

What is the greatest common factor of 16x4y3 and 12x2y7?

Mathematics

1 answer:

Marta_Voda [28]2 years ago

4 0

The greatest common factor, or GCF, is the greatest factor that divides two numbers. To find the GCF of two expression

1. List the prime factors of each number.

2. Multiply those factors both numbers have in common. If there are no common prime factors, the GCF is 1.

16x^4y^3 = ( 4*4)(x*x*x*x)(y*y*y)

12x^2y^7 = (4*3)(x*x)(y*y*y*y*y*y*y)

So common to them is 4x^2y^3

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Use the rule to write the numbers in the pattern rule:add3the

almond37 [142]

Answer:

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2 years ago

A print shop purchases a new printer for $25,000. The equipment depreciates at a rate of 5% each year. The relationship between

Pani-rosa [81]

Answer:

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

Step-by-step explanation:

Since the printer depreciates at a rate of 5% per year, I believe the stated equation is miss typed. Therefore I'll answer this with the correct equation that would represent that setting:

$y(x) = 25,000*0.95^x$

In the first year the value of the printer is:

$y(1) = 25,000*0.95^1 = 23,750$

On the second year the value of the printer is:

$y(2) = 25,000*0.95^2 = 22,562.5\\$

On the third year the value of the printer is:

$y(3) = 25,000*0.95^3 = 21,434.38\\$

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

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2 years ago

Elena bikes 20 minutes each day for exercise. Write an equation to describe the relationship between her distance in miles, D, a

ValentinkaMS [17]

Answer:

The equation to describe the relationship between Elena distance:

a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

Solution:

Given, Elena bikes 20 minutes each day for exercise.

We have to write an equation to describe the relationship between her distance in miles, D, and her biking speed, in miles per hour,

We know that, distance travelled = speed time

a. At a constant speed of 13 miles per hour for the entire 20 minutes

Her speed is 13 miles per hour.

Then, distance D miles = 13 miles per hour 20 minutes

b. At a constant speed of 15 minutes per hour for the first 5 minutes, then at 12 miles per hour for the last 15 minutes

Now, total distance travelled = distance travelled with 15 mph + distance travelled with 12 mph

c. At a constant speed of M miles per hour for the first 5 minutes, then at N miles per hour for the last 15 minutes

Now, total distance travelled = distance travelled with M mph + distance travelled with N mph

Hence, a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

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2 years ago

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Answer:

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