NB- Solution is emboldened
import java.util.Scanner;
import java.util.Random;
public class RandomGenerateNumbers {
public static void main (String [] args) {
Random randGen = new Random();
int seedVal = 0;
seedVal = 4;
randGen.setSeed(seedVal);
System.out.println(randGen.nextInt(50) + 100);
System.out.println(randGen.nextInt(50) + 100);
return;
}
}
To solve this we are going to use the formula fro the force applied to a spring:
where
is the spring constant
is the extension
Since we know the
, we can replace that in our formula and solve for
:
where
is the acceleration
is the spring constant
is the extension
is the mass
We know for our problem that
,
, and
. So lets replace those values in our formula to find
:
We can conclude that the acceleration of the block when s=0.4m is
.
1.886 to the nearest hundredth would be 2.
Answer:
domain is x = 3
Thus domain means that for every fruit cup costs $3
Range is f(20) = 60
Step-by-step explanation:
We are given;
Total students for the fruit cup party = 18
Total teachers for the fruit cup party = 2
Cost of each fruit cup =$ 3
Delivery charge = $ 10
Now, the total number of people attending the party = Total number of students + Total number of teachers
Thus;
Total number of people attending party = 18 + 2 = 20
Since cost of each fruit cup is $3.
Thus, for 20 fruit cups, the function is;
f(x) = 20x where x is cost of each fruit cup.
It means the cost of 20 fruit cups = $3 × 20 = $60
Thus, domain is x = 3
Thus domain means that for every fruit cup costs $3
Range is f(20) = 60
