D 7
A million apologies if I’m wrong half of my brain is still on vacation!
The interest due on the first payment is
.. I = Prt
.. I = 110,000*.055*(1/12)
.. I = 504.17
Then the decrease in principal resulting from the first payment is
.. 568.00 -504.17 = 63.83
and the new balance is
.. $110,000.00 -63.83 = $109,936.17
Answer:
Step-by-step explanation:
Given that from a well shuffled set of playing cards (52 in number) a card is drawn and without replacing it, next card is drawn.
A - the first card is 4
B - second card is ace
We have to find probability for
P(A) = no of 4s in the deck/total cards = 
After this first drawn if 4 is drawn, we have remaining 51 cards with 4 aces in it
P(B) = no of Aces in 51 cards/51 = 
Hence
(Here we see that A and B are independent once we adjust the number of cards. Also for both we multiply the probabilities)
Answer:
c. 35.34015106
Step-by-step explanation:
As with many problems of this nature, you only need to get close to be able to choose the correct answer. 22 minutes 45 seconds is just slightly less than 1/2 degree (30 minutes), so the tangent value will be just slightly less than tan(88.5°) ≈ 38. The appropriate choice is 35.34015106.
If you need confirmation, you can find tan(88°) ≈ 29, so you know the answer will be between 29 and 38.
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The above has to do with strategies for choosing answers on multiple-choice problems. Below, we will work the problem.
The angle is (in degrees) ...
88 + 22/60 +45/3600 = 88 + (22·60 +45)/3600 = 88 +1365/3600
≈ 88.3791666... (repeating) . . . . degrees
A calculator tells you the tangent of that is ...
tan(88.3791666...°) ≈ 35.3401510614
Many calculators will round that to 10 digits, as in the answer above. Others can give a value correct to 32 digits. Spreadsheet values will often be correct to 15 or 16 digits.
Answer:
1.79553
Step-by-step explanation:
Step 1: Write expression
log₁₀(√(69.5² - 30.5²))
Step 2: Evaluate square root
log(√(4830.25 - 930.25))
log(√3900)
log(62.45)
Step 3: Find log
log₁₀ (or log)
log(62.45) = 1.79553
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To use the table method. we find values that are easily evaluated by log₁₀
log₁₀(10) = 1
log₁₀(50) = 1.69897
log₁₀(100) = 2
So we know that log₁₀(62.45) is between 1 and 2 and greater that 1.69897.
