we know that

The company charges
cents per kilowatt-hour of electricity
Step
Find the cost for the light bulb
a) in one day


Cost=$
b) In a year



Cost=$
Step
Find the cost for the led bulb
a) in one day


Cost=$
b) In a year



Cost=$
Step
Find the difference in cost
therefore
the answer is

Answer:
$12159 per year.
Step-by-step explanation:
If I invest $x each year at the simple interest of 7.5%, then the first $x will grow for 35 years, the second $x will grow for 34 years and so on.
So, the total amount that will grow after 35 years by investing $x at the start of each year at the rate of 7.5% simple interest will be given by

= ![35x + \frac{x \times 7.5}{100} [35 + 34 + 33 + ......... + 1]](https://tex.z-dn.net/?f=35x%20%2B%20%5Cfrac%7Bx%20%5Ctimes%207.5%7D%7B100%7D%20%5B35%20%2B%2034%20%2B%2033%20%2B%20.........%20%2B%201%5D)
= ![35x + \frac{x \times 7.5}{100} [\frac{1}{2} (35) (35 + 1)]](https://tex.z-dn.net/?f=35x%20%2B%20%5Cfrac%7Bx%20%5Ctimes%207.5%7D%7B100%7D%20%5B%5Cfrac%7B1%7D%7B2%7D%20%2835%29%20%2835%20%2B%201%29%5D)
{Since sum of n natural numbers is given by
}
= 35x + 47.25x
= 82.25x
Now, given that the final amount will be i million dollars = $1000000
So, 82.25x = 1000000
⇒ x = $12,158. 05 ≈ $12159
Therefore. I have to invest $12159 per year. (Answer)
I believe the answer is 27/30
For the house A we have:
f (x) = 124270 (1.04) ^ x
Evaluating for 7, 8, 9 and 10 we have:
f (7) = 124270 (1.04) ^ 7 = 163530.8422
f (8) = 124270 (1.04) ^ 8 = 170072.0759
f (9) = 124270 (1.04) ^ 9 = 176874.9589
f (10) = 124270 (1.04) ^ 10 = 183949.9573
For house B we have:
f (x) = 114270 (1.05) ^ x
Evaluating for 7, 8, 9 and 10 we have:
f (7) = 114270 (1.05) ^ 7 = 160789.3653
f (8) = 114270 (1.05) ^ 8 = 168828.8336
f (9) = 114270 (1.05) ^ 9 = 177270.2752
f (10) = 114270 (1.05) ^ 10 = 186133.789
We observe that for years 7 and 8 the value of house A is greater than the value of house B.
Answer:
7 and 8