The attached
graph tells me that the domain is [-k,∞) and the range of this function
is (-∞,c]. The correct
answer between all the choices given is the second choice or letter B. I am
hoping that this answer has satisfied your query about this specific question.
Humor - .52
nonfiction - .32
.2 more prefer humor over nonfiction
At first, I thought this was going to be a dog of a bear of a problem,
but then I fixated it with my steely burning gaze and it fell apart for me.
The volume of a pyramid is (1/3) (base area) (height)
Each of these pyramids has the same base area and the
same height, so ...
Volume of the lower pyramid = (1/3) (base area) (height)
Volume of the upper pyramid = (1/3) (base area) (height)
Combined volume of both pyramids = (2/3) (base area) (height) .
Now, how do the pyramids relate to the rectangular prism ?
Their base area is (length x width) of the prism, and
their height is (1/2 the height) of the prism.
From here, we'll work with the dimensions of the prism ... L, W, and H .
Combined volume of the pyramids = (2/3) (L x W) (1/2 H)
= (1/3) (L x W x H) .
Volume of the prism = (L x W x H)
The pyramids occupy 1/3 the volume of the prism.
The ratio is 1/3 .
Answer:
Step-by-step explanation:
Data given and notation
represent the sample mean
represent the standard deviation for the sample
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to determine if the mean is less than 56, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
Answer:
$95.78
Step-by-step explanation:
f(t) = 300t / (2t² + 8)
t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.
$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt
$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt
$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt
$T₂ = 75 ln(t² + 4) |₅¹⁰
$T₂ = 75 ln(104) − 75 ln(29)
$T₂ ≈ 95.78
