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SSSSS [86.1K]
2 years ago
14

What is the final amount if 865 is decreased by 16% followed by a 14% increase?

Mathematics
1 answer:
Harman [31]2 years ago
6 0

Answer:

828.32

Step-by-step explanation:

865 x (1 - 0.16) x (1 + 0.14) = 828.32

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Solve 2sinx + √2 = 0
stepladder [879]
Attached you will see the solution using the trig plane and general solutions.

3 0
1 year ago
You are setting up a zip line in your yard. You map out your yard in a coordinate plane. An equation of the line representing th
vladimir1956 [14]

Solving this problem actually requires us the use of the distance formula of point to a line.

The formula is:

distance = | a x + b y + c | / sqrt (a^2 + b^2)

 

So we are given the equation:

y = 2 x + 4

rewriting:

<span>y – 2 x – 4 = 0     --> a = -2, b = 1, c = -4</span>

 

We are also given the points:

(-4, 11) = (x, y)

 

Using the distance formula at points (x, y):

distance = | -2 * -4 + 1 * 11 + -4 | / sqrt [(- 2)^2 + (1)^2]

distance = 15 / sqrt (5)

distance = 6.7

 

<span>So the tree is about 6.7 ft away from the zip line.</span>

3 0
1 year ago
How many terms in the arithmetic sequence(2,4,6,8....) will give sum of 600
andriy [413]

Answer:

  24 terms

Step-by-step explanation:

The sum of an arithmetic sequence is the average of the first and last terms, multiplied by the number of terms. The last term is given by ...

  an = a1 + (n-1)d

We have a sequence with first term a1 = 2 and common difference d = 2. So the last term is ...

  an = 2+ 2(n -1) = 2n

Then the average of first and last terms times the number of terms is ...

  Sn = 600 = n(2 + 2n)/2 = n(n+1) . . . . . . close to n²

We can solve the quadratic in n, or we can estimate the value of n as the integer just below the square root of 600.

  √600 ≈ 24.5

so we believe n = 24.

_____

<em>Check</em>

  S24 = 24·25 = 600 . . . . . . as required.

8 0
1 year ago
Three assembly lines are used to produce a certain component for an airliner. To examine the production rate, a random sample of
nikitadnepr [17]

Answer:

a) Reject H₀

b) [0.31; 3.35]

Step-by-step explanation:

Hello!

a) The objective of this example is to compare if the population means of the production rate of the assembly lines A, B and C. To do so the data of the production of each line were recorded and an ANOVA was run using it.

The study variable is:

Y: Production rate of an assembly line.

Assuming that the study variable has a normal distribution for each population, the observations are independent and the population variances are equal, you can apply a parametric ANOVA with the hypothesis:

H₀ μ₁= μ₂= μ₃

H₁: At least one of the population means is different from the others

Where:

Population 1: line A

Population 2: line B

Population 3: line C

α: 0.01

This test is always one-tailed to the right. The statistic is the Snedecor's F, constructed as the MSTr divided by the MSEr if the value of the statistic is big, this means that there is a greater variance due to the treatments than to the error, this means that the population means are different. If the value of F is small, it means that the differences between populations are not significant ( may differ due to error and not treatment).

The critical region is:

F_{k-1;n-k; 1-\alpha } = F_{2;15; 0.99} = 6.36

If F ≥ 3.36, the decision is to reject the null hypothesis.

Looking at the given data:

F= \frac{MSTr}{MSEr}= 11.32653

With this value the decision is to reject the null hypothesis.

Using the p-value method:

p-value: 0.001005

α: 0.01

The p-value is less than the significance level, the decision is to reject the null hypothesis.

At a level of 5%, there is significant evidence to say that at least one of the population means of the production ratio of the assembly lines A, B and C is different than the others.

b) In this item, you have to stop paying attention to the production ratio of the assembly line A to compare the population means of the production ratio of lines B and C.

(I'll use the same subscripts to be congruent with part a.)

The parameter to estimate is μ₂ - μ₃

The populations are the same as before, so you can still assume that the study variables have a normal distribution and their population variances are unknown but equal. The statistic to use under these conditions, since the sample sizes are 6 for both assembly lines, is a pooled-t for two independent variables with unknown but equal population variances.

t=  (X[bar]₂ - X[bar]₃) - ( μ₂ - μ₃) ~t_{n_2+n_3-2}

Sa√(1/n₂+1/n₃)

The formula for the interval is:

(X[bar]₂ - X[bar]₃) ± t_{n_2+n_3-2; 1 - \alpha /2}* Sa\sqrt{*\frac{1}{n_2} + \frac{1}{n_3} }

Sa^{2} = \frac{(n_2-1)*S_2^2+ (n_3-1)*S_3^2}{n_2+n_3-2}

Sa^{2} = \frac{(5*0.67)+ (5*0.7)}{6+6-2}

Sa^{2} = 0.685

Sa= 0.827 ≅ 0.83

t_{n_2+n_3-2;1-\alpha /2}= t_{10;0.995} = 3.169

X[bar]₂ = 43.33

X[bar]₃ = 41.5

(43.33-41.5) ± 3.169 * *0.83\sqrt{*\frac{1}{6} + \frac{1}{6} }

1.83 ± 3.169 * 0.479

[0.31; 3.35]

With a confidence level of 99% you'd expect that the difference of the population means of the production rate of the assemly lines B and C.

I hope it helps!

8 0
1 year ago
You own Everything's Coming Up Roses flower shop. Your employee makes 4 deliveries per hour. The distance between the shop and t
USPshnik [31]
I’m not entirely sure but the answer might be 72 1/2 miles. I added up 12 1/3, 8 3/4, 17 2/8, 23 2/3, and 10 5/10. And I got 72 1/2.
8 0
1 year ago
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