The solution for this problem would be:
Given that there is 99.999%.
Let denote n as the network servers and p as the reliability of each server.
So the probability that the network uptime = 1 - (1 - p)^n
Therefore, (1-p) ^n = 0.00001
a. x= log(1-.99999)÷log(1-.97)= 3.2833 is the answer
1-(1-.97)^3= 0.99999 + 0.0001 = 1
b. x = log(1-.99999)÷log(1-.88) = 5.43 is the answer
1-(1-.88)^3= 0.99 + 0.0001 = approx 1
Answer:
Step-by-step explanation:
Given that you and a friend play a game where you each toss a balanced coin.
If the upper faces on the coins are both tails, you win $1;
if the faces are both heads, you win $2;
if the coins do not match (one shows a head, the other a tail), you lose $1 (win (−$1)).
Let Y be the amount won
Then Y can take values as 1,2 and -1

The above is the probability distribution for Y.