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Scrat [10]
2 years ago
14

HELP PLEASE ASAP. A video rental store keeps a list of their top 15 movie rentals each week. This week the list includes 6 actio

n,
4 comedies, 3 dramas, and 2 mysteries. The store manager removes a copy of each of the 15 movies from the shelf, then randomly selects 3 of the 15 to
show on the display monitors in the store. What is the probability that she selected 2 comedies and 1 action movie? EXPLAIN how the probability would
change if two more comedy movies were added to the list in place of the 2 mystery movies.

NOT SURE THE ANSWER IN THE PIC.

Mathematics
2 answers:
MAVERICK [17]2 years ago
8 0

Answer:

the one selected, the one on top

Step-by-step explanation:

sashaice [31]2 years ago
5 0
The answer is the first one.
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The owner of a manufacturing plant employs eighty people. As part of their personnel file, she asked each one to record to the n
wariber [46]

Answer:

<em>Mean of the sample = 27.83</em>

<em> The variance of the the sample = 106.96</em>

<em> </em><em>Standard deviation of the sample = 10.34</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given random sample of six employees

x     26    32    29    16     45    19

mean of the sample

x^{-} = \frac{26+32+29+16+45+19}{6} = 27.83

Mean of the given data = 27.83

<u>Step(ii):-</u>

<u>Given data</u>

x           :       26         32           29           16           45        19

x - x⁻     :      -1.83      4.17        1.17       -11.83     17.17    -8.83

(x - x⁻)²  :    3.3489   17.3889   1.3689   139.9489  294.80 77.9689

∑ (x-x⁻)²  =   534.8245

Given sample size 'n' =6

The variance of given data

           S²  = ∑(x-x⁻)² / n-1  

           S^{2}  = \frac{534.8245}{6-1} = 106.9649

The variance of the given sample = 106.9649

<u> Step(iii):-</u>

Standard deviation of the given data

S = \sqrt{variance} = \sqrt{106.9649} =10.3423

Standard deviation of the sample = 10.3423

8 0
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A firm advertises for workers to address envelopes. Priscilla says she will work 100 hours. Herb will work for 80 hours. If each
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Tom:
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