10500-4500=6000
6000/250=24
So the answer is 24 months, or 2 years.
Answer:
Step-by-step explanation:
given are four statements and we have to find whether true or false.
.1 If two matrices are equivalent, then one can be transformed into the other with a sequence of elementary row operations.
True
2.Different sequences of row operations can lead to different echelon forms for the same matrix.
True in whatever way we do the reduced form would be equivalent matrices
3.Different sequences of row operations can lead to different reduced echelon forms for the same matrix.
False the resulting matrices would be equivalent.
4.If a linear system has four equations and seven variables, then it must have infinitely many solutions.
True, because variables are more than equations. So parametric solutions infinite only is possible
We know that
point A(1,1) C(3,5)
point D(-2,-4) F(0,0)
step 1
find the slope FD
m=(y2-y1)/(x2-x1)------> m=(0+4)/(0+2)----> m=4/2----> m=2
step 2
find the slope AC
m=(y2-y1)/(x2-x1)------> m=(5-1)/(3-1)----> m=4/2-----> m=2
mAC=mFD
the answer is
the slope FD is 2
Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.
The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.
Answer:
Step-by-step explanation:
I use 84+ CE
stat edit, then fill in the #s
then
vars 5
then
2'nd stat plot, on
then, click stat
Click arrow 1 time to the left to get to Calc
then click (4)(LinReg(ax+b))
then click enter 5 times
(y=-25.31428571x+1000.285714
y=-25.3x+1000.3
now, lets use computer:
y=-25.31(543)+1000.3
y=-12743.03
round to the biggest whole number )
this doesn't really work, so I will put 1999, 2000, 2001, 2002, 2003, 2004 instead of 0, 1, 2, 3, 4, 5 and do the same thing
now I get
y=-25.31428571x+51603.54286
y=-25.3x+51603.5
now, lets use computer:
y=-25.3(543)+51603.5
y=37865.6
round to the biggest whole number:
y=37866
so, year 37866
