Observe the map of the United States above. Areas indicated in red are where tornadic activity is most likely. Which

On Monday morning there were 15 inches of snow on the ground. the temperature warmed up and by Tuesday morning 36 inches had mel

lesya692 [45]

Answer:

linear function, f(x)=-3x+15

Step-by-step explanation:

its ez

4 0

2 years ago

Read 2 more answers

we are asking everyone to focus on reducing their average transaction time by 10%. the average transaction time for this locatio

Anettt [7]

Answer:

We have to get the average transaction time down to 371 seconds or 6 minutes 11 seconds.

Step-by-step explanation:

The average transaction time for this location is 6 minutes and 52 seconds.

$1\text{ minute}=60\text{ seconds}$

$6\text{ minute}=6\times 60\text{ seconds}$

$6\text{ minute}=360\text{ seconds}$

The average transaction time for this location is

$360+52=412\text{ seconds}$

The average transaction time is reduced by 10%.

$412-\frac{10}{100}\times 412=412-41.2=370.8\approx 371\text{ seconds}$

The average transaction time of this location reduced to 371 seconds.

$\frac{371}{60}=\frac{360+11}{60} =6+\frac{11}{60}$

The average transaction time of this location reduced to 6 minutes 11 seconds.

6 0

2 years ago

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Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)

UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600$

Therefore, the probability is

$P=\frac{12117600}{53524680}\\\\P=0.226$

b) We calculate the probability that are at least 2 red balls.

We calculate the probability withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations: for 1 red balls

$C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848$

Therefore, the probability is

$P_1=\frac{16138848}{53524680}\\\\P_1=0.3$

We calculate the number of favorable combinations: for none red balls

$C_7^{34}=5379616$

Therefore, the probability is

$P_0=\frac{5379616}{53524680}\\\\P_0=0.1$

Therefore, the the probability that are at least 2 red balls is

$P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6$

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056$

Therefore, the probability is

$P=\frac{44056}{53524680}\\\\P=0.0008$

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

$P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\$

Let Y, event that exactly 3 blue balls selected.

$P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\$

We have

$P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12$

Therefore, we get

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74$

8 0

2 years ago

What is the scale factor?

son4ous [18]

Scale factor is 9/15 or 3/5 in simplest form, and I think x would equal 10.

8 0

2 years ago

What is the probability of rolling an odd number and spinning "B," given the sample space below? 1 2 3 4 5 6 A A1 A2 A3 A4 A5 A6

Zielflug [23.3K]

There are 3 odd numbers out of 6 numbers and 7 B's out of 28 so

required probability = 3/6 * 7/28 = 1/2 * 1/4 = 1/8 Answer

6 0

2 years ago