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Law Incorporation [45]
1 year ago
5

A landscaper wants to find the answer to the question “How much time do people in Raleigh, North Carolina, spend doing yard work

in one week?” He asks the owners of all 120 houses in a Raleigh neighborhood. Which best describes the accuracy of the results of the survey?
Mathematics
2 answers:
Kitty [74]1 year ago
8 0

Answer:

a

Step-by-step explanation:

NISA [10]1 year ago
5 0

Answer:

A

Step-by-step explanation:

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If nothing is known about the shape of the distribution of a quantitative variable, what percentage of data fall within 2 standa
Nezavi [6.7K]
<span>At least 75% of the data will fall within 2 standard deviations of the mean. This is tricky problem. Usually when you're dealing with standard deviation, you have a bell curve, or something close to a bell curve and for such a data distribution, there will be approximately 95% of the data within 2 standard deviations of the mean. But if you don't know that you have a bell curve, you have to fall back to Chebyshev’s Theorem, which states that at least 75% of the data points will fall within 2 standard deviations of the mean for any set of numbers.</span>
7 0
2 years ago
Read 2 more answers
7526.442 rounded to the nearest hundredth
AlladinOne [14]
Number > 5 - round up
Number = 5 - round up
Number < 5 - round and keep the number the same

7526.442

Hundredth = 2nd decimal place = 4

2 < 5 
Round and keep the number the same

7526.44
3 0
2 years ago
Based on this data, what is a reasonable estimate of the probability that Nate scores 8-11 points next basketball game? Experime
Grace [21]

Answer:

8/25

Step-by-step explanation:

8 0
1 year ago
Suppose the weights of fish caught from pier 1 and pier 2 are normally distributed with equal population standard deviations. Th
madreJ [45]

Answer:

<em>H₀</em>: <em>μ</em>₁ = <em>μ</em>₂ vs, <em>Hₐ</em>: <em>μ</em>₁ > <em>μ</em>₂.

Step-by-step explanation:

A two-sample <em>z</em>-test can be performed to determine whether the claim made by the owner of pier 1 is correct or not.

It is provided that the weights of fish caught from pier 1 and pier 2 are normally distributed with equal population standard deviations.

The hypothesis to test whether the average weights of the fish in pier 1 is more than pier 2 is as follows:

<em>H₀</em>: The weights of fish in pier 1 is same as the weights of fish in pier 2, i.e. <em>μ</em>₁ = <em>μ</em>₂.

<em>Hₐ</em>: The weights of fish in pier 1 is greater than the weights of fish in pier 2, i.e. <em>μ</em>₁ > <em>μ</em>₂.

The significance level of the test is:

<em>α</em> = 0.05.

The test is defined as:

z=\frac{(\bar x_{1}-\bar x_{2})-(\mu_{1}-\mu_{2})}{\sqrt{\frac{\sigma_{1}^{2}}{n_{1}}+\frac{\sigma_{2}^{2}}{n_{2}}}}

The decision rule for the test is:

If the <em>p</em>-value of the test is less than the significance level of 0.05 then the null hypothesis will be rejected and vice-versa.

6 0
2 years ago
Lizzie has already written 120 words of an essay. She writes 5 words per minute. Write an expression to represent the total numb
worty [1.4K]

Answer:

m=24

Explanation: 120/5=24 just caculate it.

6 0
2 years ago
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