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never [62]
1 year ago
12

Basic math equations and calculations play an important role in many jobs tasks. If you were working at a grocery store and your

cash register was not automatically calculating the 20% off sale on someone's cereal--how would you solve this issue from the options listed below? If the cereal was normally $2.88, I would... 1 point Take $2.88 and times it by 80 for a sale price of $2.30. Subtract $0.20 for a sale price total of $2.68. Divide 20 from $2.88 for a sale price total of $0.15.
Mathematics
1 answer:
OverLord2011 [107]1 year ago
8 0

Given :

Price of cereal without off, C = $2.88 .

Percentage off, P = 20% .

To Find :

Price after applying 20% off.

Solution :

Final price = Initial price - 20 % of initial price

F = 2.88 - 2.88\times \dfrac{20}{100}\\\\F=2.88-0.576\\\\F=\$ 2.304

Therefore, final price after sale is $2.304 .

Hence, this is the required solution.

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Which is the correct interpretation of the x-intercepts of
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Answer:

The <em>x</em>-intercept would be at the point where there are 0 downloads in <em>x</em> days.

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The <em>x</em>-intercept of a function is the point where the graph of the function crosses the <em>x-</em>axis and the <em>y</em>-coordinate is 0.

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In this case the data provided is for the number of free downloads using the promo code (f (x), in tens of  thousands) and the time since  posting (<em>x</em> days).

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Out of five men and five women, we form a committee consisting of four different people. Assuming that each committee of size fo
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1. 10/21

2. 11/42

3.  41/42

4. 2/15

Step-by-step explanation:

Probability defines the ratio of the number of favorable outcomes to the total number of outcomes.

Combination Operations

5C2 = \frac{5! }{2! (5-2)!} = \frac{5*4*3! }{2! 3!} =\frac{5*4 }{2*1}     =\frac{20}{2}= 10

10C4 = \frac{10! }{4! (10-4)!} = \frac{10*9*8*7*6! }{4! 6!} =\frac{10*9*8*7 }{4*3*2*1}     =\frac{5040}{24}= 210

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8C2 = \frac{8! }{2! (8-2)!} = \frac{8*7*6! }{2! 6!} =\frac{8*7 }{2*1} = 4*7= 28

5C4 = \frac{5! }{4! (5-4)!} = \frac{5*4! }{4! 1!} =\frac{5 }{1} = 5

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1. Probability of forming a committee consisting of two men and two women

= \frac{5C2 * 5C2}{10C4} =\frac{10*10}{210} =\frac{10}{21}

2. Probability of forming a committee that has more women than men

(NOTE: Since the committee  desired has only 4 members, forming a committee that has more women than men can only be possible if we have  4 women, 0 men or 3 women 1 man)

= \frac{5C3 * 5C1 + 5C4*5C0}{10C4}  = \frac{10 * 5 + 5*1 }{210} = \frac{50 + 5}{210}=\frac{55}{210} = \frac{11}{42}

3. Probability of forming a committee that has at least one man

(NOTE: at least one man implies the committee must not have all women members )

=1 - \frac{5C4}{10C4}  = 1 - \frac{5}{210} = 1 - \frac{1}{42} = \frac{41}{42}

4. Probability of forming a committee with both Alice and Bob are members of the committee (NOTE: If Alice and Bob are compulsory member of the committee, there are only  two more people to join the committee from the remaining 8 people)

=\frac{8C2}{10C4} =\frac{28}{210} =\frac{2}{15}

it be like a coin toss ut a little more complicated. For every toss we have 4 outcomes from 210 possililities

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