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sammy [17]
1 year ago
12

Triangle MRN is created when an equilateral triangle is folded in half. Triangle N R M is shown. Angle N R M is a right angle. A

n altitude is drawn from point R to point S on side M N to form a right angle. The length of N S is 6, the length of S M is 2, the length of R M is x, the length of N R is y, and the length of R S is z. What is the value of x? 2 StartRoot 3 EndRoot units 4 units 4 StartRoot 3 EndRoot units 8 units

Mathematics
2 answers:
Fed [463]1 year ago
7 0

Answer:

The value of x is 4.

Step-by-step explanation:

It is given that triangle MRN is created when an equilateral triangle is folded in half.

It means original equilateral is triangle MNO and NR is a perpendicular bisector (<em>A line which cuts a line segment into two equal parts at 90°</em>).

The side length of the triangle is

NO = NS + SM = 6 + 2 = 8

Since an equilateral triangle is a triangle in which all three sides are equal and NR is a perpendicular bisector, therefore

RM = MO/2 = 8/2 = 4

The value of x is 4.

Ilya [14]1 year ago
7 0

Answer:

He is right i just took the test and its 4 units

Step-by-step explanation:

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A, C, and E

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Data on average high temperatures​ (in degrees​ Fahrenheit) in July and precipitation​ (in inches) in July for 48 cities is used
wel

Answer:

Explained below.

Step-by-step explanation:

The regression equation to predict amount of precipitation​ (in inches) in July from the average high temperatures​ (in degrees​ Fahrenheit) in July is as follows:

PRECIP​ = 2.0481​ + 0.0067 HIGH

(1)

The value of the slope of the regression line is, 0.0067.

(2)

The predictor variable in this context is the average high temperatures​ (in degrees​ Fahrenheit) in July.

(3)

The response variable in this context is the amount of precipitation​ (in inches) in July.

(4)

The slope of a regression line is average rate of change in the dependent variable with one unit change in the independent variable.

The slope here is 0.0067.

This value implies that the average rate of change in the amount of precipitation​ (in inches) in July increases by 0.0067 inches with every 1°F increase in the average high temperatures​.

(5)

Compute the mount of precipitation for a city that has an average high temperature in July of 87.31°F  as follows:

PRECIP​ = 2.0481​ + 0.0067 HIGH

             = 2.0481​ + 0.0067 × 87.31°F

             = 2.633077

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5 0
1 year ago
The length of a rectangle is 4n, and twice as long as the width. the perimeter pf the rectangle is twice as long as that of an e
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1 year ago
A control chart is developed to monitor the analysis of iron levels in human blood. The lines on the control chart were obtained
sergejj [24]

Answer:

Step-by-step explanation:

Hello!

The variable is X: iron level on human blood.

It has a mean of μ= 51.50 mg/dl and a standard deviation of σ= 3.50 mg/dl.

According to the control chart, the process should be shut down for troubleshooting when the analysis shows values X[bar]≥ 53.42 mg/dl and X[bar]≤ 49.58 mg/dl

Warnings are received at levels X[bar]≥52.78 mg/dl and X[bar]≤ 50.22 mg/dl

The system works between levels 49.58<X[bar]<53.42 and works without warnings between 50.22<X[bar]<52.78.

Using these parameters you have to analyze if the lists of sample means to see which ones are within the working values are wich ones are outside this interval.

<u>Sample 1</u>

Min= 50.15

Max= 51.99

Mean= 51.61

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>This sample's min value is below the lower limit of the warning interval but not low enough to reach action levels, the max value is within the working range.</em>

<em><u /></em>

<u>Sample 2 </u>

Min= 50.32

Max= 52.56

Mean= 51.16

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both the max and min values of the sample are within the working range without warning.</em>

<em />

<u>Sample 3</u>

Min= 50.25

Max= 53.12

Mean= 51.83

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>The max value of this sample is above the upper limit of the warning interval but does not surpass the upper bond of the troubleshoot interval. Min value is within working values.</em>

<em />

<u>Sample 4</u>

Min= 50.05

Max= 53.01

Mean= 51.70

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values surpass the warning interval but do not reach action levels</em>.

<u>Sample 5</u>

Min= 50.35

Max= 52.71

Mean= 51.37

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values are within working levels without warnings.</em>

<em />

Considering that samples reaching warning levels should be shut down as a precaution, they are classified as:

Shutdown: Sample 1, 3 and 4

Do not shutdown: Sample 2 and 5.

I hope it helps!

8 0
2 years ago
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