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sammy [17]
2 years ago
12

Triangle MRN is created when an equilateral triangle is folded in half. Triangle N R M is shown. Angle N R M is a right angle. A

n altitude is drawn from point R to point S on side M N to form a right angle. The length of N S is 6, the length of S M is 2, the length of R M is x, the length of N R is y, and the length of R S is z. What is the value of x? 2 StartRoot 3 EndRoot units 4 units 4 StartRoot 3 EndRoot units 8 units

Mathematics
2 answers:
Fed [463]2 years ago
7 0

Answer:

The value of x is 4.

Step-by-step explanation:

It is given that triangle MRN is created when an equilateral triangle is folded in half.

It means original equilateral is triangle MNO and NR is a perpendicular bisector (<em>A line which cuts a line segment into two equal parts at 90°</em>).

The side length of the triangle is

NO = NS + SM = 6 + 2 = 8

Since an equilateral triangle is a triangle in which all three sides are equal and NR is a perpendicular bisector, therefore

RM = MO/2 = 8/2 = 4

The value of x is 4.

Ilya [14]2 years ago
7 0

Answer:

He is right i just took the test and its 4 units

Step-by-step explanation:

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In the figure shown below

Answer:

A horizontal line segment M K intersects with line segment J L at their midpoint N.

∠J N M =(5x+2)°

∠ LN M=3( x+ 14)°

So, ∠J N M + ∠ LN M =180°[ These two angles form linear pair.Angles forming linear pair are supplementary.]

⇒5 x+ 2+ 3 (x+ 14) =180 [ By Substitution]

⇒ 5 x+2 +3 x+42°= 180°

⇒ 8 x=180°-44°

⇒8 x= 136°

⇒x= 136°÷8

⇒x=17°

So, ∠J N M =5×17 +2=87°

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∠J N M =∠K N L [Vertically opposite angles]

∠K N L=87°


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Explain how knowing 1+7 helps you find the sum for 7+1
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For circle O, and m∠ABC = 55°. In the figure, ∠_____ and ∠____ have measures equal to 35°.
luda_lava [24]

Answer:

In the figure ∠ABO and ∠BCO have measures equal to 35°.

Step-by-step explanation:

<u><em>The complete question is</em></u>

For circle O, m CD=125° and m∠ABC = 55°

In the figure<____, (AOB, ABO, BOA)  and <_____ (BCO, OBC,BOC) have measures equal to 35°

The picture in the attached figure

step 1

Find the measure of angle COB

we know that

m\angle COB=arc\ CD ----> by central angle

we have

arc\ CD=125^o

therefore

m\angle COB=125^o

step 2

we know that

AB is a tangent to the circle O at point A

so

ABC and ABO are right triangles

In the right triangle ABC

Find the measure of angle BCA

Remember that

m\angle BCA+m\angle\ ABC=90^o ---> by complementary angles in a right triangle

we have

m\angle ABC=55^o

substitute

m\angle BCA+55^o=90^o

m\angle BCA=90^o-55^o=35^o\\

step 3

In the triangle BCO

Find the measure of angle CBO

we know that

m\angle CBO+m\angle COB+m\angle BCO=180^o ---> the sum of the interior angles in any triangle must be equal to 180 degrees

we have

m\angle COB=125^o

m\angle BCO=m\angle BCA=35^o -----> have measure equal to 35 degrees

substitute

m\angle CBO+125^o+35^o=180^o

m\angle CBO=180^o-160^o=20^o

step 4

Find the measure of angle ABO

In the right triangle ABO

we know that

m\angle ABC=m\angle CBO+m\angle ABO ----> by angle addition postulate

we have

m\angle ABC=55^o

m\angle CBO=20^o

substitute

55^o=20^o+m\angle ABO

m\angle ABO=55^o-20^o=35^o ----> have measure equal to 35 degrees

therefore

In the figure ∠ABO and ∠BCO have measures equal to 35°.

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