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1 year ago

What is the product? 5k/6 . 3/2k^3

Mathematics

2 answers:

Romashka-Z-Leto [24]1 year ago

7 0

Pls go help me at

brainly.com/question/8858488

and your answer is 5l4k^2

Molodets [167]1 year ago

7 0

Answer: The required product is $\dfrac{5}{4k^2}.$

Step-by-step explanation: We are to calculate the following product:

$P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.$

We will be using the following property of exponents:

$\dfrac{a^x}{a^y}=a^{x-y}.$

We have

$P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.$

Thus, the required product is $\dfrac{5}{4k^2}.$

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Which value of x is in the solution set of 2x-3>11-5x

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1 year ago

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The partial factorization of x2 – 3x – 10 is modeled with algebra tiles. Which unit tiles are needed to complete the factorizati

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Answer:

(x - 5)(x + 2)

Step-by-step explanation:

x² - 3x - 10 =

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2 years ago

In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t

victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that he or she would choose the pair of socks in the center position is $p =\frac{1}{5}$

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5

The mean is $\mu = 20$

The standard deviation is $\sigma=4$

The probability, $P =0.0002$

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability $Pe = 0.0003$

The probabilities $P \approx Pe$

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

$p =\frac{1}{5}$

$=0.2$

The mean of this distribution is mathematical represented as

$\mu = np$

substituting the value

$\mu = 100 * 0.2$

$\mu = 20$

The standard deviation is mathematically represented as

$\sigma = \sqrt{np (1-p)}$

substituting the value

$= \sqrt{100 * 0,2 (1-0.2)}$

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Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

$P=P(X \ge 34 )$

By standardizing the normal approximation we have that

$P(X \ge 34) \approx P(Z \ge z)$

Now z is mathematically evaluated as

$z = \frac{x-\mu}{\sigma }$

Substituting values

$z = \frac{34-20}{4}$

$=3.5$

So using the z table the $P(Z \ge 3.5)$ is 0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

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1 year ago

Which function shows a fabric with a price of $1.25 per square yard? A table showing Price of Fleece with five columns and two r

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Answer:

Answer D is correct

Step-by-step explanation:

1: (1, 1.25) (2, 2)

So you have your first problem, your first number is x1 while your next number in the first set of parenthesis is y1. Your next set of parenthesis will be x2 and y2 like this:

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(1, 1.25) (2, 2)

Then you set up a equation like this!

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so we now plug in the numbers and get this

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--------- ---- or 0.75 BUT not 1.25 like we need!

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marusya05 [52]

Answer:

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