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leonid [27]
1 year ago
9

What is the product? 5k/6 . 3/2k^3

Mathematics
2 answers:
Romashka-Z-Leto [24]1 year ago
7 0
Pls go help me at 

brainly.com/question/8858488 

and your answer is 5l4k^2
Molodets [167]1 year ago
7 0

Answer:  The required product is \dfrac{5}{4k^2}.

Step-by-step explanation:  We are to calculate the following product:

P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.

We will be using the following property of exponents:

\dfrac{a^x}{a^y}=a^{x-y}.

We have

P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.

Thus, the required product is \dfrac{5}{4k^2}.

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Read 2 more answers
What is the value of x is in the solution set of 2x - 3 > 11 - 5x
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Step 1: Simplify both sides of the inequality.
2 x − 3 > − 5 x + 11

Step 2: Add 5x to both sides.
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