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leonid [27]
2 years ago
9

What is the product? 5k/6 . 3/2k^3

Mathematics
2 answers:
Romashka-Z-Leto [24]2 years ago
7 0
Pls go help me at 

brainly.com/question/8858488 

and your answer is 5l4k^2
Molodets [167]2 years ago
7 0

Answer:  The required product is \dfrac{5}{4k^2}.

Step-by-step explanation:  We are to calculate the following product:

P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.

We will be using the following property of exponents:

\dfrac{a^x}{a^y}=a^{x-y}.

We have

P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.

Thus, the required product is \dfrac{5}{4k^2}.

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If ΔABC ≅ ΔFDE, which of the following statements is true?
Fed [463]

Answer:

Option D) ∠B ≅ ∠D

Step-by-step explanation:

we know that

If two triangles are congruent, then the corresponding sides and the corresponding angles are congruent

so

If ΔABC ≅ ΔFDE

the corresponding angles are

∠A and ∠F

∠B and ∠D

∠C and ∠E

so

∠A ≅ ∠F

∠B ≅ ∠D

∠C ≅ ∠E

therefore

The statement that is true is ∠B ≅ ∠D

7 0
2 years ago
Read 2 more answers
The average low temperature by month in Nashville is represented by the function
malfutka [58]

Answer:

<h2>33</h2>

Step-by-step explanation:

Given the average low temperature by month in Nashville is represented by the function  f(x)=-1.4x² + 19x +1.7, where x is the month, the average rate of change is expressed as d[f(x)]/dx = 2(1.4x) + 19

d[f(x)]/dx  = 2.8x + 19

Since the number of months between March and August is 5 months and x is in months, hence we will substitute x = 5 into the resulting function to get  the average rate of change from March to  August as shown;

d[f(x)]/dx  at x = 5

= 2.8(5)+ 19

= 14 + 19

= 33

<em>Hence the average rate of change from March to August is 33</em>

4 0
2 years ago
(A) The weight of cans of vegetables is normally distributed with a mean of 1380 grams and a standard deviation of 80 grams. Wha
pychu [463]

Answer:

7.35%

Step-by-step explanation:

μ = 1380

σ = 80  

n = 15  

P(x>1410)  

= (1410-1380)/((80)/(sqrt(15)))

= 1.4524  

P(z>1.4524) = 0.4265  (from the graph)

P(z>1.4524) = 0.5 - 0.4265 = 0.0735

7 0
1 year ago
In a right triangle ?ABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: The median to side BC The length of t
ludmilkaskok [199]
The length of the angle is 12
8 0
2 years ago
Read 2 more answers
A mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt. Th
Arturiano [62]

Answer:

The probability of hitting the bullseye at least once in 6 attempts is 0.469.

Step-by-step explanation:

It is given that a mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt.

The probability of hitting bullseye in each attempt, p = 0.10

The probability of not hitting bullseye in each attempt, q = 1-p = 1-0.10 = 0.90

Let x be the event of  hitting the bullseye.

We need to find the probability of hitting the bullseye at least once in 6 attempts.

P(x\geq 1)=1-P(x=0)       .... (1)

According to binomial expression

P(x=r)=^nC_rp^rq^{n-r}

where, n is total attempts, r is number of outcomes, p is probability of success and q is probability of failure.

The probability that the dart thrower not hits the bullseye in 6 attempts is

P(x=0)=^6C_0(0.10)^0(0.90)^{6-0}

P(x=0)=0.531441

Substitute the value of P(x=0) in (1).

P(x\geq 1)=1-0.531441

P(x\geq 1)=0.468559

P(x\geq 1)\approx 0.469

Therefore the probability of hitting the bullseye at least once in 6 attempts is 0.469.

3 0
2 years ago
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