answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Thepotemich [5.8K]
2 years ago
14

1.17 A study of the effects of smoking on sleep patterns is conducted. The measure observed is the time, in minutes, that it tak

es to fall asleep. These data are obtained: Smokers: 69.3 56.0 22.1 47.6 53.2 48.1 52.7 34.4 60.2 43.8 23.2 13.8 Nonsmokers: 28.6 25.1 26.4 34.9 29.8 28.4 38.5 30.2 30.6 31.8 41.6 21.1 36.0 37.9 13.9 (a) Find the sample mean for each group. (b) Find the sample standard deviation for each group. (c) Make a dot plot of the data sets A and B on the same line. (d) Comment on what kind of impact smoking appears to have on the time required to fall asleep.
Mathematics
1 answer:
bearhunter [10]2 years ago
6 0

Answer:

a.

\bar X_F=43.7

\bar X_{NF}=30.32

b.

S_F=16.9278

S_{NF}=7.12783

c.

Attached file

d.

Apparently the practice of smoking reduces the ability to fall asleep, demanding much more time in individuals who smoke, than in those who do not smoke.

Step-by-step explanation:

a, b) For the group of smoking individuals, the average time it takes to fall asleep and the standard deviation of those times is:

\bar X_F={\frac{1}{n} \sum_{i=1}^n x_i = 43.7

S_F=\sqrt{\frac{1}{n-1} \sum_{i=1}^n (x_i-\bar{x})^2}=16.9278

a, b) For the group of non-smoking individuals, the average time it takes to fall asleep and the standard deviation of those times is:

\bar X_{NF}={\frac{1}{n} \sum_{i=1}^n x_i = 30.32

S_{NF}=\sqrt{\frac{1}{n-1} \sum_{i=1}^n (x_i-\bar{x})^2}=7.12783

c. In the attached file you can see the diagram of points for the times, in the smoking and non-smoking groups.

d. Apparently the practice of smoking reduces the ability to fall asleep, demanding much more time in individuals who smoke, than in those who do not smoke.

Download pdf
You might be interested in
The weight of a USB flash drive is 30 grams and is normally distributed. Periodically, quality control inspectors at Dallas Flas
vazorg [7]

Answer:

The critical t values are -1.746 and 1.746.

Step-by-step explanation:

Given information:

The weight of a USB flash drive is 30 grams and is normally distributed.

Population mean = 30

Sample size = 17

Sample mean= 31.9

Standard deviation = 1.8

Significance level, α=0.10

Null hypothesis: H_0:\mu=30

Alternative hypothesis: H_1:\mu\neq 30

It is a two tailed test.

The t-critical values for a two-tailed test, for a significance level of α=0.1 are  -1.746 and 1.746.

Therefore the critical t values are -1.746 and 1.746.

5 0
2 years ago
For the school's sports day, a group of students prepared 12 1/2 litres of lemonade. At the end of the day they had 2 5/8 litres
Hoochie [10]

Given :

For the school's sports day, a group of students prepared 12 1/2 litres of lemonade. At the end of the day they had 2 5/8 litres left over.

To Find :

How many litres of lemonade were sold.

Solution :

Initial amount of lemonade, I = 12 1/2 = 25/2 litres.

Final amount of lemonade, F = 2 5/8 = 21/8 litres.

Amount of lemonade sold, A = I - F

A = 25/2 - 21/8 litres

A = 9.875 litres

Therefore, 9.875 litres of lemonade were sold.

Hence, this is the required solution.

7 0
2 years ago
A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than t
belka [17]

system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y is  x+8y=68 and 3x+4y=64   .

<u>Step-by-step explanation:</u>

Here we have , A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. We need to find Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y . Let's find out:

Let the price in dollars of each large candle, x, and each small candle, y .So

A customer at a store paid $64 for 3 large candles and 4 small candles

Equation is  :

⇒ 3x+4y=64  .....(1)

At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles.

Equation is  :

⇒ x+8y=68  .......(2)

3(2)-(1) i.e.

⇒ 3(x+8y)-(3x+4y)=68(3)-64

⇒ 20y=140

⇒ y=7

So , x+8y=68  

⇒  x+8(7)=68

⇒  x=12

Therefore , system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y is  x+8y=68 and 3x+4y=64   .

7 0
2 years ago
"Mia jogs 3 kilometers in 20 minutes. There are about 0.6 miles in a kilometer. What is Mia’s approximate speed in miles per min
Lapatulllka [165]
First we need to find Mia's speed (v) in km/min

v = distance travelled/ time 
v = 3 km/20 minutes
v = 0.15 km /min

in order to convert the speed into mile/min, we need to use the conversion factor given in which for every kilometer, there is 0.6 miles. 

v = 0.15 km/min *(0.6 miles/ km) 
v =0.09 miles/min

therefore the speed in miles/min is 0.09 miles/min
4 0
2 years ago
Read 2 more answers
A tank contains 500 gallons of salt-free water. A brine containing 0.25 lb of salt per gallon runs into the tank at the rate of
Neporo4naja [7]

Answer:

0.0198 lbs per gallon

Step-by-step explanation:

amount of salt free water = 500 gallons

salt rate in = 1 gal/min

salt rate out = 1 gal/min

amount o salt in brine = 0.25 lb per gallon

Let the amount of salt in the tank be A(t) at any time t.

\frac{dA(t)}{dt} =salt rate in - salt rate out

salt rate in = 0.25 x 1 = 0.25

salt rate out = \frac{A(t)\times 1}{500}

The differential equation is given by

\frac{dA(t)}{dt} =1 - \frac{A(t)\times 1}{500}

where, A(0) = 0

So, the equation becomes

\frac{dA(t)}{dt} + \frac{A(t)}{500} = 1

Here the integrating factor is e^{\frac{dt}{500}}=e^{\frac{t}{500}}

The solution of the above differential equation is given by

A(t)\times e^{\frac{t}{500}} = \int e^{\frac{t}{500}}dt

A(t)\times e^{\frac{t}{500}} = 500\times e^{\frac{t}{500}}+C

where, C is the integrating constant.

A(t)=500+Ce^{-\frac{t}{500}}

Put, A(0) = 0

C = - 500

A(t)=500\left ( 1-e^{-\frac{t}{500} \right )

As concentration is defined as

Concentration = Quantity / Volume

C(t)=\frac{A(t)}{500}

C(t)=1-e^{\frac{-t}{500}}

Now concentration at t = 10 min

Put, t = 10 min

C(10)=1-e^{\frac{-10}{500}}

C (10) = 0.0198 lbs per gallon

Thus, teh concentration after 10 min is 0.0198 lbs per gallon.

7 0
2 years ago
Other questions:
  • Simone has 5 employees in her flower shop. Each employee works 6 4/15 hours per day. How many hours, in total, do the 5 employee
    15·1 answer
  • heather is training for a long-distance run. her data points listed below represent the days of practice, x, and the number of m
    15·2 answers
  • An 8 ft length of 4 inch wide crown molding costs $14. how much will it cost to buy 40 ft of crown molding?
    6·1 answer
  • A scuba diving instructor takes a group of students to the depth of 54.96 feet. Then they ascend 22.38 feet to see some fish. Wh
    8·2 answers
  • PLEASE HELP ASAP!! 180x=2(30÷3)+17-5•11+2÷1 = ?
    9·2 answers
  • If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
    6·1 answer
  • The least-squares regression model y =−3.4+5.2x and correlation coefficient r=−0.66 were calculated for a set of bivariate data
    10·1 answer
  • A sales completion team, aiming to reduce the shipment time of urgent orders, studies the current process and finds that the cur
    5·1 answer
  • Prove that the diagonals of a parallelogram bisect each other. The midpoints are the same point, so the diagonals _____
    7·1 answer
  • A total of $12000 was invested in two types of bonds. One pays 8% simple interest while the other pays 10.5%. Last year, the ann
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!