The teacher would need 40 centimeters of tape to hang 10 student projects.
Step-by-step explanation:
Given,
Tape used to hang projects = 36 centimeters
Number of projects hanged = 9
We will find unit rate;
9 projects = 36 centimeters
1 project = \frac{36}{9}\ centimeters
9
36
centimeters
1 project = 4 centimeters
Therefore,
Tape needed to hang 10 projects = 4*10 = 40 centimeters
The teacher would need 40 centimeters of tape to hang 10 student projects.
Keywords: unit rate, multiplication
For this problem, let x be the number of children and y for adults. Formulate the equations: 1st equation, x + y = 3,200 and 2nd equation 5x + 9y = 24,000. Re-arrange 1st equation into x = 3200 - y. Then, substitute into 2nd equation, 5(3,200-y) + 9y = 24,000. Then, solve for y. The 16,000 - 5y + 9y = 24000. Final answer is, y = 2000 adults went to watch the movie.
M=slope
In this case the slope would be $25
y=mx+b
y=25x+45
Answer: m=25
OK, so this is assuming we are considering that the first three kids to solve ARE NOT in the first day.
So we have 3 kids and it doubles
Day 1 : 6
Day 2 : 12
Day 3 : 24
Day 4 : 48
Day 5 : 96
Day 6 : 192
Day 7: 384
So it should take 7 days or a week to solve all the problems.
The equation:
(3 * 2)^x = 384
Answer:
Linear
For an increase of 1 in the x-value, what is the increase in the y-value? 2
