First, let's subtract the whole pool by the water currently in to find the water needed to fill it:
4500 - 1500 = 3000
Because we need to represent an inequality:
30m = 3000
Divide both by 30:
m = 100
It will take 100 minutes
35% chance because the company made 150 bags
Let x represent the number of type A table and y represent the number of type B tables.
Minimize: C = 265x + 100y
Subject to: x + y ≤ 40
25x + 13y ≥ 760
x ≥ 1, y ≥ 1
From, the graph the corner points are (20, 20), (39, 1), (30, 1)
For (20, 20): C = 265(20) + 100(20) = $7,300
For (39, 1): C = 265(39) + 100 = $10,435
For (30, 1): C = 265(30) + 100 = $8,050
Therefore, for minimum cost, 20 of type A and 20 of type B should be ordered.
Answer:
The relation is 'a function that is one-to-many'.
Step-by-step explanation:
From the table, we can see that element 10 i.e. y=10 in the range, corresponds to two elements i.e. x=-5, and x=5 in the domain.
In other words, the given table represents the many-to-one function as an element of the range y = 10 corresponds to more than one element in the domain.
Therefore, the relation is 'a function that is one-to-many'.
Answer:
see below
Step-by-step explanation:
1.5x + 5y = 1152
x = 4y – 2
We can substitute the second equation into the first equation
Which one-variable linear equation can be formed using the substitution method?
1.5(4y-2) +5y = 1152
Distribute
6y -3 +5y = 1152
Combine like terms
11y-3 = 1152
Add 3 to each side
11y-3+3 = 1152+3
11y = 1155
Divide each side by 11
11y/11 = 1155/11
y = 105
How many $5 raffle tickets were sold?
105 5 dollar tickets were sold
Now we need to find the number of 1.50 tickets
Which equation can be used to determine how many $1.50 raffle tickets were sold?
x = 4y – 2
x = 4(105) -2
=420-2
= 418
How many $1.50 raffle tickets were sold?
418 $1.50 tickets were sold
