Answer:
$95.78
Step-by-step explanation:
f(t) = 300t / (2t² + 8)
t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.
$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt
$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt
$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt
$T₂ = 75 ln(t² + 4) |₅¹⁰
$T₂ = 75 ln(104) − 75 ln(29)
$T₂ ≈ 95.78
Integration by substitution is an integration method meant to "undo" the chain rule for differentiation. This method is useful for some integrands containing compositions of functions.
For example, substitution is good for finding the antiderivative of 2x•cos(x^2). The quadratic function nested inside the cosine function suggests that substitution might be useful. And it is... the antiderivative is sin(x^2)+C
The answer is Choice C.
We let k be the proportionality constant for the relationship between number of hours, h and speed of the walker, s.
h = k/s
Substituting the known values,
12 = k/5
k = 60
For the second scenario,
h = k/s
Substituting the calculated value for k and the given value for speed,
h = (60)(3 miles/hour)
h = 20 hours
h = 20 hours
Therefore, it will take 20 hours to walk with a speed of 3 miles per hour.
They should have 3 daffodils and 1 rose in each bouquet and that will equal 8 bouquets.
