Question

. A rocket carrying fireworks is launched from a hill above a lake. The rocket will fall into lake after exploding at its maximum height. The rocket's height above the surface of the lake is given by h(t) = −16t 2 + 64t + 80, where h is in feet and t is in seconds

Answer 1

Answer:

Step-by-step explanation:

Since we are not told what to find, we can as well find the time taken by the rocket to reach its maximum height as shown

The rocket reaches its maximum height when the velocity is zero

v = dh/dt

v = -32t+64

Since v = 0 at maximum height

0 = -32t+64

32t = 64

t = 64/32

t = 2secs

Hence the rocket reaches the maximum height after 2secs