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2 years ago

An inspector checks 98 cell phones and finds 2 of them not working. If a company

Mathematics

1 answer:

insens350 [35]2 years ago

8 0

Answer:

Step-by-step explanation:

Use ratio method

98:2

850:x

so, x = (850 x 2) divided by 98 = 17.3469388

Round it to nearest whole number = 17

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A recipe for casserole calls for 2 cups of rice. The recipe makes 6 servings of casserole. how many cups of rice will you need t

ss7ja [257]

You will need 3.333.... cups of rice to make 10 servings of casserole.

Explanation

The recipe which makes 6 servings of casserole, needs 2 cups of rice.

Suppose, you need $x$ cups of rice for making 10 servings of casserole.

Now, the equation according to the ratio of "cups of rice" to the "servings of casserole" will be.....

$\frac{x}{10}=\frac{2}{6}\\ \\ 6x= 2*10=20\\ \\ x=\frac{20}{6}=3.333.....$

So, you will need 3.333.... cups of rice to make 10 servings of casserole.

5 0

2 years ago

You and a friend are playing a game by tossing two coins. If both coins land

Novosadov [1.4K]

c. No. You have a probability of winning, while your friend has a
probability of winning.
Or it’s A

3 0

2 years ago

Read 2 more answers

People are arriving at a party one at a time. While waiting for more people to arrive they entertain themselves by comparing the

Marina CMI [18]

Answer:

=(k−1)*P(X>k−1) or (k−1)365k(365k−1)(k−1)!

Step-by-step explanation:

First of all, we need to find PMF

Let X = k represent the case in which there is no birthday match within (k-1) people

However, there is a birthday match when kth person arrives

Hence, there is 365^k possibilities in birthday arrangements

Supposing (k-1) dates are placed on specific days in a year

Pick one of k-1 of them & make it the date of the kth person that arrives, then:

The CDF is P(X≤k)=(1−(365k)k)/!365k, so the can obtain the PMF by

P(X=k) =P (X≤k) − P(X≤k−1)=(1−(365k)k!/365^k)−(1−(365k−1)(k−1)!/365^(k−1))=

(k−1)/365^k * (365k−1) * (k−1)!

=(k−1)*(1−P(X≤k−1))

=(k−1)*P(X>k−1)

6 0

2 years ago

Why is a lame elephant like adding 10 and 3

Lorico [155]

Answer:because it wants to know the answer cause maybe it’s a little elephant child

Step-by-step explanation:

5 0

2 years ago

The probability of a train arriving on time and leaving on time is 0.8. The probability that the train arrives on time and leave

kkurt [141]

Answer:

0.9524

Step-by-step explanation:

Note enough information is given in this problem. I will do a similar problem like this. The problem is:

The Probability of a train arriving on time and leaving on time is 0.8.The probability of the same train arriving on time is 0.84. The probability of the same train leaving on time is 0.86.Given the train arrived on time, what is the probability it will leave on time?

Solution:

This is conditional probability.

Given:

Probability train arrive on time and leave on time = 0.8
Probability train arrive on time = 0.84
Probability train leave on time = 0.86

Now, according to conditional probability formula, we can write:

$P(Leave \ on \ time | arrive \ on \ time)$ = P(arrive ∩ leave) / P(arrive)

Arrive ∩ leave means probability of arriving AND leaving on time, that is given as "0.8"

and

P(arrive) means probability arriving on time given as 0.84, so:

0.8/0.84 = 0.9524

This is the answer.

5 0

2 years ago