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elixir [45]
2 years ago
6

Each of the three oldest children sleeps in a twin bed. They all need bed sheets. A brand of sheets is on sale for “Buy one get

one at 50% off”. If each sheet costs $18.00, how much will two sheets cost? How much will six sheets cost?
Another brand of sheets is on sale 30% off with a regular price of $18.00 per sheet. Which is a better deal, the previous example or this one? Explain.
Mathematics
1 answer:
kow [346]2 years ago
7 0

Answer:

Step-by-step explanation:

Two sheets will cost: $27

The value of the first sheet will be $18, and since the other sheet is half off it will be half of the original value: 18 * 0.5 = 9.

Then you add the values together: 18 + 9 = 27.

Six sheets will cost: $81

For every sheet that is the original value there is a sheet that is half off. So since there are six sheets, 3 of the sheets will be $18 and three of them will be $9. We already know that 18+9=27, so just multiply that value by 3.

27*3= 81

Better deal: The second example

In the second example sheets are 30% off. 30% of 18 is $6. Subtract that value from 18 and you will get $12. In the second example one sheet is $12.

If we multiply that value by 2, we will get $24.

In the first example, two sheets costs $27, while in the second example two sheets cost $24. Since the cost is less for the second example, the second example is the better deal.

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Complete the following proof. Given: Points R, S, T, Q on circle O Prove: m\overarc RS + m\overarc ST + m\overarc TQ + m\overarc
LekaFEV [45]

Answer:

360°

Step-by-step explanation:

From the figure attached,

R, S, T and Q are the points on a circle O.

Since, "measure of an arc of a circle is equal to the measure of the angle subtended by the arc at the center."

By this statement,

m(\widehat{RS})=m(\angle ROS)

m(\widehat{ST})=m(\angle SOT)

m(\widehat{TQ})=m(\angle TOQ)

m(major arc RQ) = m(∠QOR)

Now m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major arc RQ) = m(\angle ROS)+m(\angle SOT)+m(\angle TOQ)+m(\angle QOR)

Since sum of all angles at a point = 360°

m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major arc RQ) = 360°

4 0
2 years ago
An escalator in the subway station has a vertical rise of 195ft 9.5in, and rises at an angle of 10.4 degrees. How long is the es
MrRa [10]
The escalator is 98 feet long
5 0
2 years ago
A craft vendor must sell at least $300 worth of merchandise to make a profit. Scarves sell for $10 each and hats sell for $20 ea
valina [46]
There is a missing graph in the problem given. However, we can simply solve the equation using the given data.

Items to be sold: scarves and hats. Minimum of 20 items sold in all.
Scarves sell for 10 each and hats sell for 20 each. Must sell at least 300 worth of merchandise to make profit. 

Let s represent scarves and h represent hats.

10s + 20h <u>></u> 300
s + h <u>></u> 20

We use inequality because the problem states "at least". 

s + h = 20
10s + 20h = 300

s = 20 - h
10(20-h) + 20h = 300
200 - 10h + 20h = 300
10h = 300 - 200
10h = 100
h = 100/10
h = 10

s = 20 - h
s = 20 - 10
s = 10

s + h <u>></u> 20
10 + 10 <u>></u> 20

10s + 20h <u>></u> 300
10(10) + 20(10) <u>></u> 300
100 + 200 <u>></u> 300

7 0
2 years ago
Read 2 more answers
What’s the 38th term of the arithmetic sequence 31,40,49,58?
Trava [24]

Answer:

a_3_8=364

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference

we have

31,40,49,58,...

Let

a_1=31\\a_2=40\\a_3=49\\a_4=58

we have that

a_2-a_1=40-31=9

a_3-a_2=49-40=9

a_4-a_3=58-49=9

so

The common difference is equal to 9

We can write an Arithmetic Sequence as a rule:

a_n=a_1+d(n-1)

where

a_n is the nth term                                                              

a_1 is the first term

d is the common difference                        

n is the number of terms

Find the 38th term of the arithmetic sequence

we have                  

a_1=31\\d=9\\n=38              

substitute the values

a_3_8=31+9(38-1)

a_3_8=31+9(37)

a_3_8=364

3 0
2 years ago
Which expression can be used to find the sum of the polynomials? (9 – 3x2) (–8x2 4x 5)
SIZIF [17.4K]

For this case we have:

Polynomial 1: P (x) = 9-3x ^ 2

Polynomial 2: Q (x) = - 8x ^ 2 + 4x + 5

Sorting the polynomials:

Polynomial 1: P (x) = - 3x ^ 2 + 9

Polynomial 2: Q (x) = - 8x ^ 2 + 4x + 5

Adding term to term (similar) we have:

P (x) + Q (x) = (- 3-8) x ^ 2 + (0 + 4) x + (9 + 5)\\P (x) + Q (x) = - 11x ^ 2 + 4x + 14

Answer:

A (x) = P (x) + Q (x) = - 11x ^ 2 + 4x + 14


7 0
2 years ago
Read 2 more answers
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