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2 years ago

10

(6-2.7h)+(-1.3j-4) ?

2 answers:

SIZIF [17.4K]2 years ago

8 0

Answer:

−2.7h−1.3j+2

Step-by-step explanation:

Murljashka [212]2 years ago

5 0

Answer:

= 2 - 2.7h - 1.3j

Step-by-step explanation:

(6-2.7h)+(-1.3j-4)

we solve the question with the BODMAS

BRACKET

OF

DIVISION

MULTIPLICATION

ADDITION and

SUBTRACTION

(6-2.7h)+(-1.3j-4)

Solve the bracket first

= 6 - 2.7h - 1.3j - 4

Now we collect like terms

= 6 - 4 - 2.7h - 1.3j

= 2 - 2.7h - 1.3j

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2 years ago

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A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km and then stops for a 90.0-min na

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Answer:

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(b) 9 km/h

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$v=\frac{d}{t}$

where d is the total distance traveled and t is the total time needed.

$d=\frac{4.00}{1.75}=2.29$ km/h

For part (b) you have to calculate the running time (T) , which is the total time of the race minus the nap time:

The nap time in hours is:

90/60 = 1.5 h (because there are 60 minutes in one hour)

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Let t1 represent the time before the nap and t2 the time after the nap:

t1+t2 = T

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But v2=2v1 (because after the nap the rabbit runs twice as fast)

You have to solve the system of equations:

t1=0.25-t2 (I)

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Replacing (I) in (II)

v1(0.25-t2)=0.50

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0.25v1-1.75=0.50

Solving for v1:

v1 = 9 km/h

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