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2 years ago

There are 64 animals at the zoo. ⅜ of the animals are birds. How many birds are at the zoo?

Mathematics

2 answers:

insens350 [35]2 years ago

8 0

Answer:

Step-by-step explanation:64/1*3/8= 192/8

192/8= 24

24 birds at the zoo

xxTIMURxx [149]2 years ago

5 0

Answer:

Step-by-step explanation:

3/8 of the 64 total animals at the zoo are birds.

To solve, this, multiply 3/8 and 64

3/8*64=24

Another way to solve would be to make a proportion

3/8=x/64

Multiply both sides by 64 to get x by itself

64(3/8)=(x/64)64

24=x

So, 24 out of the 64 animals are birds

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Sue Jones is insured for bodily injury in the amount of 10/20. She is at fault in an accident in which Albert Smith is injured.

lianna [129]

For this case, what you should know is that Sue Jones insurance covers half of the expenses. Equivalently, her insurance covers:
10/20 = 1/2 = 0.5
Therefore, we have then that
a. for Albert
0.5 * (12000) = $ 6000
b. for Sam
0.5 * (8000) = $ 4000
c. total
The sum of the results of parts a and b
$ 6000 + $ 4000 = $ 10,000
answer
$ 6000
$ 4000
$ 10,000

4 0

2 years ago

Read 2 more answers

According to a 2013 study by the Pew Research Center, 15% of adults in the United States do not use the Internet (Pew Research C

Pavel [41]

Answer:

a) For this case we can use the binomial model since we assume independent events and the same probability for each trial is the same p =0.15

b) $P(X=0)=(10C0)(0.15)^0 (1-0.15)^{10-0}=0.1969$

c) $P(X=3)=(10C3)(0.15)^3 (1-0.15)^{10-3}=0.1298$

d) $P(X \geq 1)= 1-P(X$

And using the result from part a we got:

$P(X \geq 1)= 1-P(X$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n p)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

For this case we can use the binomial model since we assume independent events and the same probability for each trial is the same p =0.15

Part b

For this case we want this probability:

$P(X=0)$

And replacing we got:

$P(X=0)=(10C0)(0.15)^0 (1-0.15)^{10-0}=0.1969$

Part c

For this case we want this probability:

$P(X=3)$

And replacing we got:

$P(X=3)=(10C3)(0.15)^3 (1-0.15)^{10-3}=0.1298$

Part d

For this cae we want thi probability:

$P(X \geq 1)$

And we can use the complment rule and we got:

$P(X \geq 1)= 1-P(X$

And using the result from part a we got:

$P(X \geq 1)= 1-P(X$

4 0

2 years ago

Erica can run 1 6 6 1 start fraction, 1, divided by, 6, end fraction of a kilometer in a minute. Her school is 3 4 4 3 start

Brut [27]

Her school is 2/3 miles away

2/3=4/6miles

So we need to find out how long it will take for her to run home from school...

School=4/6 miles

In 1 minutes she can run 1/6 miles

1min=1/6miles

In 2 minutes she can run 1/6+1/6 miles (1/6+1/6=2/6)

2min=2/6miles

3min=3/6miles

4min=4/6miles

It will take Erica 4 minutes to run 4/6 miles, so it'll take her 4 minutes to get home.

8 0

2 years ago

a coast Guard ship patrols an area of 125 square miles. the are the ship patrols is a square. about how long is each side of the

Salsk061 [2.6K]

31.25 is answer , rounded answer would be 30 miles each side.

5 0

2 years ago

Let X represent the amount of time until the next student will arrive in the library parking lot at the university. If we know t

Ber [7]

Answer:

The probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

Step-by-step explanation:

The random variable X is defined as the amount of time until the next student will arrive in the library parking lot at the university.

The random variable X follows an Exponential distribution with mean, μ = 4 minutes.

The probability density function of X is:

$f_{X}(x)=\lambda e^{\lambda x};\ x\geq 0, \lambda >0$

The parameter of the exponential distribution is:

$\lambda=\frac{1}{\mu}=\frac{1}{4}=0.25$

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10}{0.25e^{-0.25x}}\, dx$

$=0.25\times \int\limits^{\infty}_{10}{e^{-0.25x}}\, dx\\=0.25\times |\frac{e^{0.25x}}{-0.25}|^{\infty}_{10}\\=(e^{-0.25\times \infty})-(e^{-0.25\times 10})\\=0.0821$

Thus, the probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

3 0

2 years ago