Emanuel was charged \$32$32dollar sign, 32 for a 14\dfrac29 \text{ km}14 9 2 km14, start fraction, 2, divided by, 9, end fract
2 answers:
Answer:
The cost per kilometer was $2.25
Step-by-step explanation:
<u><em>The correct question is</em></u>
Emanuel was charged $32 for a 14 2/9 km
What was the cost per kilometer?
To find out the cost per kilometer (unit rate) divide the total cost by the total kilometers
<em>Convert mixed number to an improper fraction</em>
<em>Find the unit rate</em>
therefore
The cost per kilometer was $2.25
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Answer:
0.3114
Option d is right
Step-by-step explanation:
Let X be the time spent on a treadmill in the health club
Given that research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard deviation of 5.4 minutes
Also given that X is normal
the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.
round off to two decimals tog et
the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill is 0.31
Hence option d is right
Answer:
Maximum Area of the basketball court = 1250 ft²
Maximum area of the playground = 400 ft²
The basketball is 3.125 times larger than than the playground.
Step-by-step explanation:
The diagram representing the description is attached to this solution.
The big rectangle represents the basketball court.
The small rectangle represents the playground.
Let the length and width of the basketball court be y and x respectively.
The length and width of the small playground will be (y-30) and (x-5) respectively
The Area of the basketball court is
A(x, y) = xy
But, 2x + y = 100
We can maximize the Area by turning the two variable function into a one variable function and substituting for y in the Area equation.
2x + y = 100
y = 100 - 2x
A(x, y) = xy
A(x) = x(100 - 2x) = 100x - 2x²
A(x) = 100x - 2x²
At maximum point, (dA/dx) = 0 and (d²A/dx²) < 0, that is, negative.
(dA/dx) = 100 - 4x = 0
(d²A/dx²) = -4 < 0
Hence, it's a maximum point.
At maximum point,
(dA/dx) = 100 - 4x = 0
100 - 4x = 0
4x = 100
x = 25 ft
y = 100 - 2x = 100 - 2(25) = 100 - 50 = 50 ft
Hence, the length and width of the basketball court that maximizes the Area are 50 ft and 25 ft respectively.
For the small playground,
The length = (y - 30) = (50 - 30) = 20 ft
The width = (x - 5) = (25 - 5) = 20 ft
Maximum Area of the basketball court = xy = (50)(25) = 1250 ft²
Maximum area of the playground = (y-30)(x-5) = (20)(20) = 400 ft²
Ratio of the Areas = (1250/400) = 3.125
The basketball is 3.125 times larger than than the playground
Hope this Helps!!!
