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2 years ago

∠A and ∠B are complementary angles of right triangle ABC, cos A = 0.83, and cos B = 0.55. What is sin A + sin B?

Mathematics

2 answers:

sergiy2304 [10]2 years ago

4 0

As the angles are complementary sin A = cos B and sin B = cos A

so sin A + sin B = 0.55 + 0.83 = 1.38

MissTica2 years ago

3 0

Answer:

$sin(A)+sin(B)=1.38$

Step-by-step explanation:

Let

A, B and $90\°$ the measures of the angles in a right triangle

we know that

$m$ ------> by complementary angles

$sin(A)=cos(B)$

$sin(B)=cos(A)$

In this problem we have

$cos(A)=0.83$

$cos(B)=0.55$

therefore

$sin(A)=0.55$

$sin(B)=0.83$

$sin(A)+sin(B)=0.55+0.83=1.38$

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If h(x) = 6 – x, what is the value of (h circle h) (10)?

Marta_Voda [28]

Answer:

Step-by-step explanation:

hoh(x) = h(h(x)) = 6 - h(x) = 6 - (6-x) = 6 - 6 + x = x

then

hoh(x) = x

then

hoh(10) = 10

5 0

1 year ago

Find the sum of the first 63 terms of –19, -13, -7 …

boyakko [2]

The Given Sequence is an Arithmetic Sequence with First term = -19

⇒ a = -19

Second term is -13

We know that Common difference is Difference of second term and first term.

⇒ Common Difference (d) = -13 + 19 = 6

We know that Sum of n terms is given by : $S_n = \frac{n}{2}(2a + (n - 1)d)$

Given n = 63 and we found a = -19 and d = 6

$\implies S_6_3 = \frac{63}{2}(2(-19) + (63 - 1)6)$

$\implies S_6_3 = \frac{63}{2}(-38 + (62)6)$

$\implies S_6_3 = \frac{63}{2}(-38 + 372)$

$\implies S_6_3 = \frac{63}{2}(334)$

$\implies S_6_3 = {63}(167) = 10521$

The Sum of First 63 terms is 10521

4 0

2 years ago

The following table shows the number of hours some teachers in two schools expect students to spend on homework each week: Schoo

Lerok [7]

Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

$IQR=Q_3-Q_1=16-6.5=9.5$

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

$IQR=Q_3-Q_1=15.5-8=7.5$

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

4 0

2 years ago

What is the volume of a cylinder with base radius 222 and height 666? either enter an exact answer in terms of \piπpi or use 3.1

Leno4ka [110]

In this question, it is given that the base radius is 2 , height is 6 and the value of pi is 3.14 .

And we have to find the volume of the cylinder, and for that, we have to use the following formula

$V = \pi r^2 h$

Substituting the values of pi,r and h, we will get

$V = 3.14(2)^2 * 6 = 75.36 \ cubic \ units$

3 0

2 years ago

Read 2 more answers

A food distributor is being sued for racial discrimination because 12% of newly hired candidates are not white when 53% of all a

Musya8 [376]

Answer:

Check Explanation

Step-by-step explanation:

A) The null hypothesis would be that the proportion of newly hired candidates that are not white is not significantly different from the proportion of the applicants that are not white & there is no significant evidence that the company's hiring practices are discriminatory.

Mathematically,

H₀: μ₀ = 0.53

And the alternative hypothesis would be that there is a significant difference between the proportion of newly hired candidates that are not white is not significantly different from the proportion of the applicants that are not white. More specifically, that the proportion of newly hired candidates that are not white is significantly less than the proportion of applicants that are not white & there is significant evidence that the company's hiring practices are indeed discriminatory.

Mathematically,

Hₐ: μ₀ < 0.53

B) The two errors that can come up in this hypothesis testing include -

Type I error: We reject the null hypothesis because we obtain that the proportion of newly hired candidates that are not white is significantly less than the proportion of applicants that are not white and conclude that there is indeed significant evidence that the company's hiring practices are discriminatory when in reality, there is no significant difference and hence, no discrimination.

Type II error: We accept the null hypothesis (fail to reject the null hypothesis) because we obtained that there is no significant difference between the proportion of newly hired candidates that are not white & th proportion of applicants that are not white and conclude that there is no discrimination in the company's hiring practices when in reality, there is significant difference in the stated proportions above and significant evidence that there is indeed significant evidence that the company's hiring practices are discriminatory.

C) The power of the test increases as the significance level reduces. This is because t-statistic increases as significance level reduces.

D) The standard error of the mean used in computing the t-score is given as

σₓ = (σ/√n)

It is evident that as the value of n increases, the standard error reduces and this widens the effect of the test, hence, the power of the test increases.

Hope this Helps!!!

7 0

2 years ago