All categories

2 years ago

∠A and ∠B are complementary angles of right triangle ABC, cos A = 0.83, and cos B = 0.55. What is sin A + sin B?

Mathematics

2 answers:

sergiy2304 [10]2 years ago

4 0

As the angles are complementary sin A = cos B and sin B = cos A

so sin A + sin B = 0.55 + 0.83 = 1.38

MissTica2 years ago

3 0

Answer:

$sin(A)+sin(B)=1.38$

Step-by-step explanation:

Let

A, B and $90\°$ the measures of the angles in a right triangle

we know that

$m$ ------> by complementary angles

$sin(A)=cos(B)$

$sin(B)=cos(A)$

In this problem we have

$cos(A)=0.83$

$cos(B)=0.55$

therefore

$sin(A)=0.55$

$sin(B)=0.83$

$sin(A)+sin(B)=0.55+0.83=1.38$

You might be interested in

Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is $[ {\rm{\$ 10,000 , \$ 15,000}]$ , where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

$\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}$

$=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4$

(b) The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

$\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)$

$=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8$

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

$\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}$

(d) The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

5 0

2 years ago

A piece of string that is 132 inches long is cut into 3 pieces. The second piece of string is twice as long as the first piece.

gladu [14]

Your equation is like so A x 2 x 3 = 132
A is the length of your first string B is the length of your 2nd string (A x 2) and C (3) is the length of your 3rd string which is (A x 3).
A x 2 x 3 = 132
/3 /3
A x 2 = 44
/2 /2
A = 22.
A(22) x 2 x 3 = 132. 22 x 2 is 44. 44 is the length of line 2. 22 x 3 is 66, 66 is the length of line 3. 22 + 44 + 66 = 132. 66 is the length of your longest piece.

4 0

2 years ago

What are two reasons someone might purposely choose a HIGHER monthly payment?

Allisa [31]

To earn extra money a month

4 0

2 years ago

Read 2 more answers

John's average for making free throws in a basketball game is .80. In a one-and-one free throw situation (where he shoots a seco

Illusion [34]

The probability of John making the first and missing the second is:
$P(makes\ 1\ basket)=0.8\times(1-0.8)=0.16$

4 0

2 years ago

Read 2 more answers

18. A normal population has a mean of 80.0 and a standard deviation of 14.0. a. Compute the probability of a value between 75.0

mixer [17]

Answer:

a) 40.17% probability of a value between 75.0 and 90.0.

b) 35.94% probability of a value 75.0 or less.

c) 20.22% probability of a value between 55.0 and 70.0.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 80, \sigma = 14$