Question

∠A and ∠B are complementary angles of right triangle ABC, cos A = 0.83, and cos B = 0.55. What is sin A + sin B?

Answer 1

As the angles are complementary sin A = cos B and  sin B = cos A

so sin A + sin B =  0.55 + 0.83 =  1.38

Answer 2

Answer:

$sin(A)+sin(B)=1.38$

Step-by-step explanation:

Let

A, B and $90\°$ the measures of the angles in a right triangle

we know that

$m$ ------> by complementary angles

so

$sin(A)=cos(B)$

$sin(B)=cos(A)$

In this problem we have

$cos(A)=0.83$

$cos(B)=0.55$

therefore

$sin(A)=0.55$

$sin(B)=0.83$

$sin(A)+sin(B)=0.55+0.83=1.38$