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2 years ago

6

The graph below represents the distance in miles (y), Jonathan travels on his bike in minutes (x). The table represents the dist

ance in miles (y).
Terrance travels on his bike in minutes (x).

1 answer:

mr Goodwill [35]2 years ago

8 0

Answer:

We cant see the question

Step-by-step explanation:

You cant post images because we can't see them

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What number is 0.72 more than 0.971?

bearhunter [10]

Answer:

1.691

Step-by-step explanation:

.971 + .72

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2 years ago

Read 2 more answers

George bought 9 apples that cost 50 cents each.

Natasha2012 [34]

He has 9 apples so we add .50 cents 9 times.
If we count this money-wise we would get 4.50, so if he paid with a $5 bill he would recieve 50 cents

4 0

2 years ago

A triangular piece of rubber is stretched equally from all sides, without distorting its shape, such that each side of the enlar

OverLord2011 [107]

Answer:

The area of the enlarged triangle is $4$ times the original area

Step-by-step explanation:

we know that

The scale factor is equal to divide the measurement of the length side of the enlarged triangle by the the measurement of the length of the corresponding side of the original triangle

In his problem

Let

x------> the length side of the original triangle

so

2x-----> is the length of the corresponding side of the enlarged triangle

$scale\ factor=\frac{2x}{x}=2$

$scale\ factor> 1$ -------> that means is increasing

The scale factor squared is equal to the ratio of the area of the enlarged triangle divided by the area of the original triangle

so

Let

m-------> the area of the enlarged triangle

n------> the area of the original triangle

r-------> scale factor

$r^{2} =\frac{m}{n}$

we have

$r=2$

substitute

$2^{2} =\frac{m}{n}$

$m=4n$

therefore

The area of the enlarged triangle is $4$ times the original area

8 0

2 years ago

Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw

PolarNik [594]

Answer:

Using <u>backward reasoning</u> we want to show that <em>"We can never get nine 0's"</em>.

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

<u>There were 9 </u><u>0's</u><u>:</u>

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

<u>There were 9 </u><u>1's</u><u>:</u>

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

<u />

5 0

2 years ago

N experiment was conducted to test the effect of a new stain remover. Twenty stains were treated with stain remover A and stain

Klio2033 [76]

Answer:

For this case the statistic calculated is $t= 1.37$

$p_v =0.17$

So the p value is a very high value and using the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and there is enough evidence to conclude that we have a difference between the two means at 10% of significance.

Step-by-step explanation:

Data given and notation

$\bar X_{A}$ represent the mean for the sample for A

$\bar X_{B}$ represent the mean for the sample B

$s_{A}$ represent the sample standard deviation for the sample A

$s_{B}=$ represent the sample standard deviation for the sample B

$n_{A}=20$ sample size for the group poisoned

$n_{B}=20$ sample size for the group unpoisoned

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the two means are equal or not , the system of hypothesis would be:

Null hypothesis: $\mu_{A} - \mu_{B} =0$

Alternative hypothesis: $\mu_{A} - \mu_{B} \neq 0$

For this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{A}-\bar X_{B}}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

For this case the statistic calculated is $t= 1.37$

Statistical decision

The significance level is 0.1 $\alpha=0.1$ , but we can calculate the p value for this test. The first step is calculate the degrees of freedom, on this case:

$df=n_{A}+n_{B}-2$

The p value on this case is given

$p_v =0.17$

So the p value is a very high value and using the significance level given $\alpha=0,1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and there is enough evidence to conclude that we have a difference between the two means at 10% of significance.

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2 years ago