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mariarad [96]
2 years ago
10

George bought 9 apples that cost 50 cents each.

Mathematics
1 answer:
Natasha2012 [34]2 years ago
4 0
He has 9 apples so we add .50 cents 9 times.
If we count this money-wise we would get 4.50, so if he paid with a $5 bill he would recieve 50 cents
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Make w the subject of the formula y-aw=2w-1
kipiarov [429]
Answer: <span>w = [ y + 1] / [a + 2]

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</span>
1) given <span>formula: y-aw=2w-1

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2w + aw = y + 1

3) common factor w:

w (a + 2) = y + 1

4) divide both sides by (a + 2):

w = [ y + 1] / [a + 2]
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6 0
2 years ago
A computer store decides to increase the prices of all the items it sells by 15%. The store manager uses matrices to prepare the
Nitella [24]
The manager could perform scalar multiplication on Matrix A, using the scalar 1.15.

Increasing the price by 15% would mean we are taking 100% of the value + another 15%; 100+15 = 115%; 115% = 115/100 = 1.15.

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4 0
2 years ago
A manager records the number of hours, X, each employee works on his or her shift and develops the probability distribution belo
Reika [66]

Answer:

c. 2

Step-by-step explanation:

Given : X = No. of hours worked

           No. of people work for the manager = 50

           X = 3, 4 , 5 , 6 , 7, 8

           P(X) = 0.1 , ? , 0.14 , 0.3 , 0.36 , 0.06

To Find : No. of people work for four hours

Solution : First understand the fact that sum of all probabilities is equal to 1

So, sum of all values of P(X) = 1

⇒0.1+?+0.14+0.3+0.36+0.06 = 1

⇒0.96+? = 1

⇒?= 1-0.96

⇒? = 0.04

So, the probability of no. of people worked for 4 hours is 0.04.

⇒P(4)=0.04

Thus , To calculate no. of people work for four hours :

0.04\times 50

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5 0
2 years ago
Read 2 more answers
Estimate the value of 9.9 squared x 1.79
Helen [10]
9.9^2X1.79
9.9^2=98.01
98.01X1.79=175.4379
7 0
2 years ago
Read 2 more answers
Webassign find the area of the region bounded by the parabola y = x2, the tangent line to this parabola at the point (6, 36), an
Dvinal [7]
First find the tangent line

dy/dx=2x
at x=6, the slope is 2(6)=12
so
use point slope form
y-y1=m(x-x1)
point is (6,36)
so
y-36=12(x-6)
y-36=12x-72
y=12x-36

alright, so we know they intersect at x=6
and y=12x-36 is below y=x^2

so we do \int\limits^6_0 {x^2} \, dx - \int\limits^6_0 {12x-36} \, dx = \int\limits^6_0 {x^2-(12x-36)} \, dx = \int\limits^6_0 {x^2-12x+36} \, dx =
[\frac{x^3}{3}-6x^2+36x]\limits^6_0=(\frac{6^3}{3}-6(6)^2+36(6))-(0)=\frac{216}{3}-216+216= 72+0=72

the area under the curve bounded by the lines and the x axis is 72 square units
4 0
2 years ago
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